124 44 5MB
English Pages 136 [147] Year 2016
Annals of Mathematics Studies Number 3 1
ANNALS OF MATHEMATICS STUDIES Edited by Emil Artin and Marston Morse 1. Algebraic Theory of Numbers, by
H erm an n W ey l
3. Consistency of the Continuum Hypothesis, by 6.
The Calculi of Lambda-Conversion, by
7. Finite Dimensional Vector Spaces, by 10. Topics
in
Topology, by
K urt G o d e l
A lo n zo C h u r c h
Paul
R.
H a lm o s
S o lo m o n L e fsc h e t z
11.
Introduction to Nonlinear Mechanics, by N.
14.
Lectures on Differential Equations, by
and N.
K rylo ff
S o lo m o n
B o g o l iu b o f f
L efsc h etz
15. Topological Methods in the Theory of Functions of a Complex Variable, by M a r s t o n M o r s e 16.
Transcendental Numbers, by
17.
Probleme General de
19.
Fourier Transforms, by S.
20.
la
C arl
L u d w ig
S ie g e l
Stabilite du Mouvement, by M. B och n er
and
K;
A . L ia p o u n o f f
C h a n d r a sek h a r a n
Contributions to the Theory of Nonlinear Oscillations, Vol. I, edited by S. L e f s c h e t z
21.
Functional Operators, Vol. I, by
22.
Functional Operators, Vol. II, by
23.
Existence Theorems in Partial Differential Equations, by
J o h n von N e u m a n n J ohn
von
N eum ann D orothy
L.
B e r n s t e in 24.
Contributions to the Theory of Games, Vol. I, edited by H. W. A. W. T u c k e r
25.
Contributions to Fourier Analysis, by A. A. P. C a l d e r o n , and S. B o c h n e r
26.
A Theory of Cross-Spaces, by
27.
Isoperimetric Inequalities in Mathematical Physics, by G. G. S z e g o
28.
Contributions to the Theory of Games, Vol. II, edited by H. A. W. T u c k e r
29.
Contributions to the Theory of Nonlinear Oscillations, Vol. II, edited by S. L e f s c h e t z
30.
Contributions to the Theory of Riemann Surfaces, edited by et al.
Zygm und,
W.
and
T r a n su e , M . M o r se ,
R obert Sch atten
31. Order-Preserving Maps and Integration Processes, by 32.
K uhn
Curvature and Betti Numbers, by
K. Yano
and S.
E dw ard
B och n er
P o lya
and
Kuhn
and
L . Ah lfo rs
J.
M cShane
ORDER-PRESERVING MAPS AND IN T EG R A T IO N PROCESSES By EDWARD J. McSHANE
Princeton, New Jersey Princeton University Press 1953
Copyright, London:
1953,
by Princeton University Press
Geoffrey Curriberlege, Oxford University Press L. C. Card 53-6583
Printed in the United States of America
CONTENTS
Introduction
3
Chapter I.
7
Partially Ordered Sets and Systems 1 . 2.
Partial Orderings and Lattices Completeness
7 9
3*
Types of Convergence
1^
h.
Closure
21
5-
Continuity
23
6.
Partially Ordered Groups
26
7- Linear Systems, Multiplicative Systems and Algebras within Partially Ordered Sets Chapter II.
Definition of the Mapping
32 36
8.
The Postulates
36
9*
U-elements and L-elements
39
1 0 . Lattice Properties of the Classes of U- and
b1
L-elements 1 1 . Definition of the Mapping or Integral
Chapter III.
Lattice Properties, Convergence and Measurability
^5 ^8
1 2 . Further Lattice Properties of the Classes of
131 ^.
U-elements and L-elements
^8
Lattice Properties of the Class of Summable Elements
53
Monotone Sequences of Summable Elements
15- Dominated Convergence 1 6 . Structure of the Set of Summable Elements 17- Measurable Elements
v
55 59
6b 65
vi
CONTENTS
Chapter IV.
Algebraic Operations
18.
Interchange of Order of Operations
19•
Addition, Scalar Multiplication and Binary
69 69
Multiplication
71
20.
Summability of Products
76
21.
Operations on Measurable Elements
77
Chapter V.
Real-valued Functions
81
22.
Integrals of Real-valued Functions
81
23.
Measurable Functions and Lebesgue Ladders Fubini1s Theorem
87
2k . Chapter VI.
Applications
93 95
25.
Measure in Locally Compact Spaces
26.
Functions on Locally Compact Spaces
ioo
27-
A Non-absolutely Convergent Integral
1 03
28.
Remarks on Operators in Hilbert Spaces
1 08
29.
Spectral Resolution of a Bounded Hermitian Operator
30.
125
Spectral Resolution of Complex Partially Ordered ♦-algebras with Unit
Bibliography
118
Spectral Resolution of Real Partially Ordered Algebras with Unit
32.
113
Bochner’s Generalization of the Bernstein-Widder Theorem
31•
95
131 155
ORDER-PRESERVING MAPS AND INTEGRATION PROCESSES
INTRODUCTION The various definitions of the Lebesgue integral and its generali zations may be classified, if we wish, into two subsets, one making essen tial use of some kind of norm or modulus, and another, less numerous, in which the central role is played by some order relation. For example, bocnner’s mLegrau (..bocnner ij 01 a iuncLion wnose values lie on a uanacn space involves formation of successive approximations which converge in the sense of the norm in the Banach space. Again, in Stone's treatment [Stone 1] of the integral, order properties are first used to define a norm in a func tion space, and then the integral is defined by means of a convergence according to this norm. On the other hand, the definition of the Riemann integral by use of the Darboux upper and lower integrals rests on order properties, and so does Daniell's definition [Daniell 1] of integral, gen eralizing the Lebesgue and Radon (or Lebesgue - Stieltjes) integrals. The Perron integral, too, is defined as the function which is simultaneously the lower bound of a set of overestimates and the upper bound of a set of underestimates, and thus is one of those making essential use of order. Daniell develops the integral by assuming that a subset E of the lattice F of all real-valued functions on a set T is mapped into the set of real numbers by an order-preserving mapping I satisfying certain requirements. He then shows how this mapping can be extended, giving a mapping I whose domain contains E and whose range is contained in the reals; this mapping is order-preserving, and also has the closure and continuity properties expressed in the well-known convergence theorems of the Lebesgue theory. Thus Daniell's theory can be regarded as a study of a special case of the following problem. We are given two partially ordered sets F and G, and an order-preserving mapping I of a subset E of F into G. We seek conditions on E, I , F, and G that will enable us to extend the domain of definition of IQ, producing say a mapping I of FQ into G, in such a way that the enlarged domain FQ shall have some useful closure properties and the extended mapping I shall have some useful kind of continuity property on its domain. It is to the study of this problem that the following pages are devoted. Because it is
^References are to the brief bibliography at the end of the study. 3
k
INTRODUCTION
an exploitation of the order properties almost exclusively, it is to be expected that the territory which it more or less naturally takes in is in part different from that covered by the integration theories based largely on norms.
If it gracefully furnishes interesting applications, its exist
ence is justified.
We believe that the examples exhibited in the last
chapter will show this to be the case. For the sake of simplicity we restrict the problem by assuming that
F
is a lattice.
tially ordered set
This is not a great restriction, since every par
F
can be embedded in a lattice, and if the process of
extension yields a domain containing points of that lattice not in the original
F
we have the privilege of ignoring them.
one of the applications in the last chapter
F
In fact, in all but
is isomorphic with the
lattice of extended-real-valued functions on some domain. with regard to
G
is different.
tion 29 the values of on a Hilbert space.
I
The situation
For example, in the application in Sec
lie in the set
G
of bounded hermitian operators
These may be regarded as defining quadratic functions
on Hilbert space, and thus embedded in the lattice of real functions on the Hilbert space.
But the chief importance of the extended mapping
that its values also are bounded Hermitian operators.
I
is
If we knew only that
the values corresponded to some real function on the Hilbert space, the result would have been without interest. that the image space
G
Therefore we refrain from assuming
is a lattice.
This in fact constitutes one of the chief differences between the present treatment of integration and others that have preceded it.
Thus,
for example, in the fundamental paper of H. Freudenthal [Freudenthal 1 ] there is developed a type of Riemann-Stieltjes integral with values in a "partially ordered module," which is not merely a partially ordered linear system as we here define the term, but is a lattice.
Likewise, M. H. Stone
[Stone 3] and HidegorS Nakano [Nakano 1 , 2 ] define integrals whose values lie in a lattice. is not trivial.
The difference, insofar as it concerns our present aims, For example, a (suitably closed) commutative algebra of
hermitian operators is actually a lattice, but this is by no means super ficially evident; while on the other hand it Is obvious that this algebra is partially ordered. To the best of my knowledge, there are two important publications on integration processes involving partially ordered spaces which are not lattices. These are [Bochner 1 ] and [Bochner and Ky Fan 1 ] . In both of these a Riemann-Stieltjes type of integral is used, in the former to extend the Bernstein-Widder theorem, and in the latter to obtain a representation of the general distributive order-preserving mapping of functions continuous on an interval (or circumference) into a partially ordered space.
The
principal result of [Bochner 1] is very close to the application here in Section 3 0 .
INTRODUCTION
5
One result of working with partially ordered sets instead of lattices is that we must first develop an adequate theory of closure, completeness, convergence and continuity.
This we do in the first chapter,
a trifle more extensively than is absolutely essential for later use.
It
is our strong suspicion that some interesting portions of lattice theory can be usefully generalized to less restricted partially ordered sets. Our methods are of course related to those of Daniell.
Some
rather drastic changes necessarily result from replacement of the lattice of real-valued functions on a set
T
by the general lattice
F*
and the
replacement of the real number system by the partially ordered set
G.
But
in addition to these there are a couple of changes that would affect the discussion even of the case considered by Daniell. the use of auxiliary partial orderings. by the relation
The set
valued functions on an interval )>.
where by
f »
F
is partially ordered
in terms of which it is a lattice; but there may also
be other partial orderings useful as auxiliaries. relation
One of these concerns
J
For example, the real
are partially ordered by the usual
But we can also partially order them by the relation g
we mean that to each point
a neighborhood on which the supremum of
g
x*
of
J
»,
there corresponds
does not exceed the infimum of
f . When we develop the Lebesgue-Stielt jes integral by extending the ele mentary integral on step-functions, we use systems of step-functions directed by
»
or by its reverse
«,
and thereby avoid the sometimes
tedious discussion of the phenomena at the boundaries of the intervals of constancy of the step-functions.
This same device is also of service in
the study of the Riemann-Stielt jes integral, as will be shown in a joint paper with T. A. Botts [McShane and Botts l]. for
»,
With other special meanings
the auxiliary partial ordering also proves useful in the other
examples in this paper. The other departure from Daniell*s pattern is a relaxation of the requirement that the set integral
I
E
of elementary functions on which the elementary
is defined should be a lattice.
This relaxation can be
pictured with the help of the family of polynomials on an interval Since the (real) functions continuous on such functions
g-],g2,gj
the function
point is the middle one of the values of But if
e^,e2,
a polynomial.
and
e^
J.
form a lattice, for any three
mid(g 1 ,g2 ,g^)
whose value at each
g 1 ,g2,g-*> is also continuous.
are polynomials their "middle" is not necessarily
However, in this case, if
f - mid ( e ^ e ^ e ^ )
J
f
is any function such that
has a positive lower bound, by Weierstrass* theorem we
can find a polynomial e on J such that f - e and e - mid(e 1 ,e2 ,e^) both have positive lower bounds on J. Our substitute for the requirement that
E
element
be a lattice in e
F
is just the analogue of demanding that such an
exist (and the dual requirement, where
a positive lower bound).
mid ( e ^ e ^ e ^ )
Even this we ask only when
I^e^
and
- f
has
I0 ^e2 ^
INTRODUCTION
6 have a common upper bound.
This relaxation is useful, for example, in
studying the spectral resolution of bounded hermitian operators on a Hilbert space, as discussed in Section 2 9 ; for here the natural starting point is the family of polynomials in the operator.
It is also useful in the appli
cations studied in Sections 3 0 , 31 and 3 2 , for similar reasons. the requirement that there exist an when
IQ (e1)
and
I0 (e2)
e
Because
as just described is imposed only
have a common bound, the integral obtained is
not necessarily absolutely convergent.
In fact, as one application of the
general theory we obtain (in Section 2 7 ) an integral which closely resembles the Perron integral, and may be identical with it. Our principal type of convergence based on order properties shows a close affinity with "pointwise" rather than "uniform" convergence. instance, in Section 3 we show that when
F
For
is the set of extended-real-
valued formations on some domain, order-convergence is the same as pointwise convergence.
When
F
is the set of bounded hermitian operators on
Hilbert space, order-convergence coincides with (eventually) bounded strong convergence.
Accordingly, the spectral resolution of an operator
we obtain serves to put the Borel-measurable functions [-||B||,||B||] f(B),
f
B
which
on the interval
into correspondence with operators, designated as usual by
forming a commutative algebra; the integral composes each
f(B)
out
of limits of linear combiiiations of certain projection-operators forming the resolution of the identity for
B.
When we consider algebras of hermitian
operators (as in Section 31), we map the elements of the algebra on Borelmeasurable functions on a product of certain intervals; this is in contrast with the Gelfand-Neumark representation by means of simpler (i.e., continu ous) functions on a more complicated domain. bounded hermitian operator and
For instance, if
E^, - « < A. < »
identity, the least algebra containing
B
B
is a
is its resolution of the
and all the
E^
is by the
present theory represented by the Borel-measurable functions on the interval [-||B||,||B||]. would require
The representation by continuous functions on a domain D
D
to be of much greater complexity.
These considerations may lend some interest to the theorems in Sections 31 and 32 concerning partially ordered algebras, since we again obtain theorems which, when interpreted in the specialization to operators on Hilbert space, give the "strong" rather than the "uniform" theory. The examples which we have considered do not exhaust the possi bilities, nor have the individual examples been studied as exhaustively as possible. It is hardly to be expected that the present approach would yield startlingly new results in such well-worked fields as LebesgueStieltjes integration or the spectral resolution of a bounded hermitian operator.
In familiar settings we are content to obtain familiar theorems;
the novelty, if any, lies In the unification, whereby such apparently diverse processes as Perron-type integration and spectral resolution appear as instances subsumed under a single theory.
C H A P T E R
I
PARTIALLY ORDERED SETS AND SYSTEMS
$ 1 . PARTIAL ORDERINGS AND LATTICES
A binary relation partial ordering; of (1 .1 )
(a)
If
(b)
If
F
>
between pairs of elements of a set
F
is a
if it satisfies the conditions
a > b
and
a > b
b > c
and
then
b > a
a > c.
then
a = b.
(Sometimes (1 .1 a) alone is used as the definition of a partial ordering; then relations satisfying (l.la,b) are called proper partial orderings. But we shall adhere to the terminology above.) ing of that in
F,
>
F),
and
a > b
is defined to mean that
If
>
is a partial order
a > b
ora = b,
is another partial ordering.
It is reflexive
and is the same as
was itself reflexive.
>
if
>
partial ordering whose symbol includes the mark ive, but the absence of
=
=
we
see
(a> a for all
(as in
a
Thus any ))
is reflex
in the symbol does not imply the absence of
reflexivity. Let b > a.
be partially ordered by
We verify at once that
element all
F
b
x
b
unique.
Lower bounds and the infimum of
It S
when it exists, will be designated
has just two members, say
usually write a V b for V s and a A b for As . If a set F is partially ordered by ^>,
S = (a,b),
we
sois eachsubset
FQ .
But the situation here is not as simple as the analogous one in topology. For if S is a subset of F Q , it may have a supremum when regarded as a subset of
Fq
it may have a
but not when regarded as a .subset of supremum in F Q
F, or vice versa;
when regarded as a subsetof F Q 7
and a
or
I.
8 different (1 ) F 2 < x
PARTIALLY ORDERED SETS AND SYSTEMS
supremum in F
when regarded as a subset of F.
the rationals, F 2
] such that the elements of
D),
and for two such elements
^
F
are the
and ^ 2,
the
relation ^ y 2 moans that ^ (6))^2 (5) f*0I> all 6 in D. It is obvious that > is a partial ordering of F. Since we shall not have any use for cartesian products except when the sets are partially ordered, we shall usually abbreviate the product symbol to X.F., partial ordering being understood as above. For tion” of
on
"projection" of tions on
F^
(2 .6 )
Ffl S
shall mean on
F^
F D,
of
Let F.
S
F, the "projec of F,
the
S.
[F,X
partially ordered sets a subset
for a subset
the meaning of the in
shall mean the set consisting of the projec
of the elements of THEOREM.
(6);
0 0
be the cartesian product of
[Ffl
6 in
In order that S
D.
Let
it isnecessary and sufficient that for each the projection of
S
on
F^
S
be
have a supremum in
6
in
shall have a supremum
(with respect to >$); in. this case, the supremum of S is the element of F whose projection on F^ is the supremum of the projection of is also true.
S
on
F ^ • The dual
12
I.
PARTIALLY ORDERED SETS AND SYSTEMS
If S has a supremum
4>
for each
an upper bound for the projection of let
b*
S
6
in
be an upper bound for the projection of
4(6) for
6
D , ^ 6',
in
while
6'
S
in
F ^ ,.
4'(6') = b*. Then 4' ^ ^,4(6'). That is,
D,
in
Let
is an
is
and
4'(6) =
upper
4(6*) is the supremum of the projection of S on F ^ . Conversely, if 4(6) = V[projection of S on F^] for each 6 , 4 is an upper bound for S. Given any other upper bound 4' of S, we have for each 6 in D that 4'(6) y^4(6) for all \p In S, so 4'(6) is an upper bound for the projection of S on F ^ , and 4(6) • Hence 4 is the supremum bound for
of
S.
S,
4' ^
4(6)
the projection
F ^ . Fix a
so
and
The dual is established similarly. COROLLARY.
(2.7)
If for each
6
D
in
the set
F ft
is
Dedekind-complete under the partial ordering
the o 13 also Dedekind complete.
cartesian product If a lattice
F
does not contain a greatest element, we can
adjoin a new ideal element (usually denoted by all
x
in
adjoin one.
F.
Likewise if F
If
F
enlarged lattice.
More: 0,
F
I > x
each non-empty set
S C F
0
for we can
ct)
n(ce) = V(f(oel):at
exists, and also
we define The lower
be a net of
F.
o-lim sup f(oe) « in A
dually.
A(n(oe):ct
in
If for each in A)
A
a
and
exists,
to be A(n(a):oe in A). o-lim inf f (a) is defined ° ln A
To simplify the notation we shall usually abbreviate the symbol o-lim sup f(a)
to
o-lim sup^fta)
th? ln ^ lower limit.
or to
o-lim sup f,
and likewise for
16
I.
(3-3)
PARTIALLY ORDERED SETS AND SYSTEMS in
A)
is a net of ele
ments of a partially ordered set
COROLLARY.
If
F,
and
o-lim sup^fCa)
(f(ce):ot
and
o-lim inf^fta)
exist, then
( i)
o-lim supa f(a) > o-lim inf^f (a);
(ii)
o-lim^fCa)
and exists if and only if
o-lim supa f(o«)
and
o-lim in^f(ce)
equal, and in that case
are
o-limtff(ce)
is
equal to their common value. Conclusion (i) is evident.
Consider (ii).
lower limits are equal, the set
(n(a):ct
dually defined set
A)
(3*1)•
(m(a):a
Conversely, if
in
exists, let
For each
n
we have
n(oe')< n,
and therefore
o-lim sup^f (a)
N,
If the upper and
defined in (3 *2 ) and the
A)
have all the properties specified in
o-lim^ffa)
in (3 .1 ).
in
in
f(ce)
M and
N
is eventually
he as stated
< n,
o-lim supa f(a) < n.
< A N = o-lim^f (a) .
a*
so for some
Hence
Similarly o-lim infa f (a) >o-lim^f (a)
which with (i) completes the proof. In particular, if
F
is a complete lattice,
limits of every net of elements of
F
theupper and lower
are both defined.
There is some interest in finding the relationship between con vergence of a net in a product-space and convergence of its projections into the factor spaces. (3 .L)
THEOREM. spaces, [F,>]
Fg
F-, 6
Let
0
in
D
be a collection of
being partially ordered by
>^ ;
be the cartesian product
(f(a):oe
in
A)
and let
? =
Let
be a net of elements of
F.
In order
-M-
that
f
be o-convergent to an element
f
of
F, it
is necessary and sufficient that ( i)
there exist elements that eventually,
(ii)
If Suppose We choose for
h*
is satisfied.
If
m',n'
in
of
F
D,
such and
the projection
f^ of
on
F, shall be o-convergent to the ® * * projection f^ of f on F ^ . D is a finite set, (i) may be omitted. first that
o-lim f(ot) = f *.
any element of
M
and for
Let h"
are the projections of
they are directed by If
6
for each f
h',h"
h* < f (ct) < h” ,
be as in (3 .1 ).
M,N
F^
are
m',n'
m,n
N;
(i)
respectively on
respectively, and by (2 .6 ) V
are inrespectively, there exist
tively whose projections on
M,N
any element of
in M,N
Fg
= f^ respec
respectively, so eventually
3m1
and to have
is eventually true f
m^
>^,
For each finite subset
D - D .
of finite to be
directed by
m^
all elements for
M^,N^
and for each
true that
so
17
^ n ‘* Hence (ii) holds. Conversely, suppose (i) and (ii) satisfied.
there A
TYPES OF CONVERGENCE
f*
that
f(oe) > m. * — is o-convergent to f .
is finite we can take
DQ
and hM ] . This is easily seen to for supremum; and if The set
N
m
is in M,
it
can be defined analogously,
Two special cases occur often enough in later pages to make it worth while to mention them as examples: (3-5)
COROLLARY.
If
H
Is the set of all extended-
real-valued functions on a domain ordering that in
Dg,
h 1 < h2
if
then a directed system
ments of
H
and only
if
Bg.
H
If
a domain
D^,
with the partial
h ^ x ) < h2 (x)
for all
(ha :ce in
is convergent to an element h^(x)
converges to
hQ (x)
A) hQ
x
of ele of
H
for each
if
x
In
Is the set of all real-valued functions on
D^,
ordered as just described, then a
directed system (ha :oe in o-convergent to an element
A) hQ
of elements of H is of H if and only if
it is "eventually dominated” (that is, there exist elements for all
h' a
and
h”
of
H
beyond a certain
verges to
hQ (x)
for all
x
such that a 1)
h 1 < ha < h”
and
Ha (x)
con
in Dg.
The second statement is a specialization of (3«*0first, if we take
h1
Again, let
F
ordered product of
n
a l 9 ’‘‘9 ments of
L
an ln F. Then
is isotone. (3-6)
constantly
-»
and
h"
constantly
be a lattice, and let copies of
F.
Let
Fn
So is the +».
be the partially-
L = (L(a1, ..., an ):
be a lattice combination defined on n-uples of ele maps Fn on F. It is easy to see that the mapping
We now prove THEOREM. With the notation above, if
(a1 (oe) :a
in
A ) , ..., (an (a) :ot in
A)
elements with the respective o-limits the net (L(a1 (a), ..., an (.a)) :a vergent to L ( a ‘1, ..., a fn ) .
in
are nets of a^,
A)
..., a'n ,
is o-con-
18
I.
PARTIALLY ORDERED SETS AND SYSTEMS
For each number directed by each
mj
>,
in
j
in the set
Mj
and each
n^
in
1, ..., n,
there are sets
\/Mj = /\Nj = a 1 . and such that for
respectively, having Nj
it is eventually true that
m^
y,
and
a - x
If
x ^ a
then
a + x + b)>a + y + b
+ b < a - y and
The four statements -y + x y B> -y > -x
If a - y + b. -x < -y;
x > y,
With
by setting
a = b = B,
replacing
x
by
z = y
and
y
then
x + y > a + b.
x > y, x - y > 0 , are equivalent.
in (6 .ib> we obtain
this implies -y
+ b.
y ^ b,
by
-x < -y. -x
Now
a - x + b
a + b
and
x + y > x + b,
whence (ii) follows; and (Iii)
is an obvious consequence of (Ii). (6 .3 )
COROLLARY. the pair F
Let
a,b,x,y
be members of F + .
If
(x,y) has either a supremum or an infimum In
which is a member of
F ,
then all four pairs
( x, y, ) ( - x , - y ) , (a + x + b, a + y + b,) [a-x+b, a-y+b) all belonging to F + ,
have both Infima and suprema, and the equations
a +
(x V y) + b = (a + x + b) V (a + y + b)
a -
(x V y) + b = (a - x + b) A (a - y + b)
(-x) V i-y) = -(x A y )
28
I.
PARTIALLY ORDERED SETS AND SYSTEMS
and their duals are satisfied.
Assume first that is a lower
is a lower bound for {x,y}
is
x V y
exists and is in
bound for -x
and
a - x + b and
is
< a - (x V y )
x+b) A (a - y
(a
-
we
findthat
x A y
+b .
a-(x V y )
+ b
Every upper bound for
lower bound for
That is,
{a - x + b,
a - (x \/y) + b =*
+ b) . In particular, if we set y - ix V y) + x,
exists and is
F+ . By (6.2111),
-y, so by (6.2i)
a - y + b.
) x V y , so by (6.1b) every
a - y + b)
F+
x V / y + x A y ^ x + y.
is a commutative group,
-(x V y )
In particular, if
a = y
and
b = x,
being therefore in
F . When addition is commutative this yields the last equation in the conclusion. that
Since
(a - x + b) V
a = b * 0
x Ay
exists, we can dualize the proof above and show
(a - y + b)
exists and is
permits applying the above proof to and
y
a - (x A y )
-
Letting
gives us the second-last equation in the conclusion.
by
-y
-x
and
-y;
replacing
This
x
by
-x
in the equation just established furnishes the remaining
conclusion. The equivalents of
f+ , f“
and
|f|
as usually understood in
function-spaces or in lattices do not always exist in partially ordered groups,
butwe follow the
(6.10
usual path when this is possible.
DEFINITION.
Let F+
partially ordered space such that F+ ,
f V 0 and
be a group embedded In a F.
If
f
(-f) V 0
Is a member of
F+
both exist and are in
we define f
f * f \/ 0 ,
f’ - (-f)V 0 , If I - f+ + f REMARK. (-f \/ B)
By (6 .3 ),
exists and belongs
(6 .5 )
COROLLARY.
if either of the suprema f\ / 0 toF+ ,
When f+
and
so does the other. and
f”
are defined, the
relations f+ > 0, f” > 0, |f| > 0, f+ - f” = -f“ + f+ = f are satisfied. The inequalities are obvious. so by (6 .3 )
f + (-f)V 0 + 6
By hypothesis,
= (f + [-f] + $) V
(-f)\/ 0
(f + 0 + 0),
or
f + f" - f+ . Also by (6 .3 ), S+ (-f)V 0 + f = (0 + [-f] + f ) V (0 + 0 + f), or f" + f = f+ . These imply the conclusion.
exists,
6. (6.6)
THEOREM.
PARTIALLY ORDERED GROUPS Let
F+
29
be a group under
contained in a partially ordered set of
elements of
F
ftnot necessarily in F+ ),
+
F.
and be
If each pair
F+ has a supremum and an infimum in (6 .1 b) is equivalent to
the statement If
(6.1b*) (a
a,b,x,y,z
are In
- x + b) < (a When
F+
F+
x > y A z,
and
y + b) V
(a - z +b ) ,
Is a lattice embedded in
then
and dually. (6 .1 b) is
F,
equivalent to If
i6. 1b") a - x
a,b,x,y
+ b < a - y
are in
F+
and
x > y,
then
+ b.
Clearly (6.1b) implies (6.1b1), and it implies (6.1bn) by (6 .2 ).
y A z
If
exists, the hypothesis s = y A z)
implies (with
that
"s < y x ^ y
A
s < z
and
z,
implies
s < x "
so by (6 .lbr) half the con
clusion of (6 .1 b) holds; the other half is established dually. a
lattice and (6 .1 b") holds,
c
-
(x A y )
for
+ d>c-x + ' d
c - ( x A y ) + d > ( c - x
and
eachc,d^x,y c-(x A y) +
+ d ) \ / ( c - y + d).
Is similarly established, we first replace a
-
y + b,
b
-
(a - x + b) V
then replace
a - (x A y) + b. equality holds. satisfied.
c
by
is
we have
d ^
c - y + d,so
x
by d
a - x + b by
a;
or (a - x + b) V
and
y
by
we
obtain
(a
- y + b) >
The reversed inequality has already been established, so Then the statement in (6 .ib•) concerning Infima Is
The other statement is established dually, so (6.1b*) holds,
and therefore so does (6 .1 b). (6 .7 )
F+
F+
In the dual statement, which
band
(a - J + b) + a _ 0
-b*
+ f2< 0.
If we define
b
0, so
b =
have an upper bound fj - b» < 0
f^ - b* + f2 , wehave
b < f1
and
To establish (ii) use induction.
Suppose it valid for
n = k - 1,
b*
and By (i),
and let
**19 **’9 **k e^einen^s su°h that each pair of consecutive members has an upper or a lower bound (hence, by (I), has both) in F . By the induction hypothesis, the set bound bound
(f1, ... f ^ )
has a lower bound
c
and an upper
c 1 in F+ . Also by hypothesis, the pair tfk-1,fk ) a lower d and an upper bound d' in F+ . Then f^_1 is an upper bound
for the pair Clearly
(c,d),
so by (I) the pair has a lower bound
h < c < f^
lower bound for
(1=1,
..., k - 1)
(f1, ..., f^).
and
b
b < d < f^,
in F
so
.
b is
a
The existence of an upper bound Is
established dually, and by Induction (Ii) Is valid. The connection between bounds and the group operation Is inter esting enough to justify a digression, even though the results of the next few paragraphs are not essential to later proofs. For each such that and
F^
Fa ,Fk
a
and
a b
In
F+
let
Fa
be the set of all
in F+
have a common upper or lower bound in F
have a common element
c,
and
. If F0 + s are arbitrary members of
a f,bT
respectively, by (6 .7 ) the five elements
common upper bound In
b
F+ ,
so
a*
is in
F^
a',a,c,b,b' and
b1
in
have a F& . Hence
F, = F 0 . Thus the partially ordered group F^ Is classified into D o # + mutually exclusive classes F& . If a is in the class F^ containing the pair (0,a) Then
has
bf
and a lower bound
a = -[b' - a] + [b*] = [a - b] - [-b],
brackets being
^ 0*
either of the forms versely, If
x
0 , so
x
and
an upper bound
.If such that a - b,
So every element in
a
can be represented in and
has either of these forms,
c
Is an upper bound for
- b is
d
are
]> 0.
Con
F^,
there are elements
in F ^ .
Then
c
It follows that
It is in fact an invariantsubgroup.
For if a
c,d
- d > 0
In
and
F+
c -d >
F^
Is a subgroup of
Is
in F^
and
b inF+ such that b > 0 and b ) a. and -x + b + x > -x + 0 + x = 0, so
-x + a + x
For each set
is again in F ^ .
F& ,
if
b
and
F e they have a common upper bound d in F , d - b and d - c cL + > 0, and so b - c = -(d - b) + (d - c) is in F,^. Conversely, if is
in F^, b - a and
0
and
andtherefore b
the sets
Fa
subgroup
F^.
a —< c + a,
have a common upper bound
are the cosets into which
F+
is in
in
c are both
In
b - a
F+ .
x is
F , there exists an element Then -x + a + x < - x + b + x
b < c + a
x
F^ b are in
c > a, c > 0, d < 0, d < b.
so
the quantities in square
F^ c
is in
0,
F .
where
a and
c - d, -d + c,
b in
c
in F+ ,
are so
Fa .Thisshows that is classified by the Invariant
6.
PARTIALLY ORDERED GROUPS
31
The next theorem shows that (6.1c) follows from (6.la,b), provided that
F+
(6.8)
has a certain closure property.
THEOREM.
Let F+
be a group contained In a
Dedekind complete partially ordered set satisfying (6.1a) and (6.1b). and F+
b
are in
and
F+ and
a < x < b)
holds, so that over, if by
^
set
S1
a < b,
and
the set
is Dedekind closed.
(x : x
and
S2
are subsets of
and having upper bounds in (-x : x
S1
in
and
More
directed
and
in
S 1}, then
F.
F+
F+ , x2
a
in
Then (6.1c)
F + isa group embedded in
(x., + x2 : x 1 in
is the set
F
Assume that whenever
S
is the
S2 )and
S_
V S j , V S 2 ,V S
and
A S _ all exist, and
Vs - V s 1 + Vs 2 , As_ = - vs 1 . It is clear that (6.1c) follows from the statements in the last sentence, so this is all we need to prove. The sets directed by and
S2
and
b 2 are upper bounds in
is an upper bound for
S
VS.,, V S 2 , V s VS., + V S 2
belong to
and A s _
and
is
F+
for
and
all exist in F
is an upper bound for
S 1; for all
a2
in
S2
S,
V S ]> V S 1 + V S 2 -
The
established, so equality holds, and
so
we have
whence’ -a1 + V S > a2 , and -a1 + V S > V s2 * T*1®31 so V S - V S 2 ^ a., . This holds for all a 1 in S 1, so VS.,,
S_
S^
-b1
is a
S _ . By the hypothesis of Dedekind completeness of
Dedekind closure, to
S 1, S2
and
F
and
belong
V s a 1 + a2,
> a i + \/S2, \/S - V S 2 >
reverse inequality was previously the first equation established. The
second is proved analogously. The equations in the last conclusion of (6.8) can be established without assuming the Dedekind closure of the sets a < x < b)
provided the sets
S1
merely the greatest element in
and
S^.
S2
(x : x
in
F+
are finite, for then
and VSi
is
This and (6.8) might lead to the
suspicion that (6.1c) is always a consequence of (6.la,b).
This is not so;
if we omit the hypothesis concerning Dedekind closure in (6.8) the equa tions in the conclusion may fail even when all the infima and suprema mentioned in them exist.
For example, let
reals under addition, and let plus two elements
Q_«|>Q2
F
F+
consist of the group of
consist of the reals with the usual order
wltl1 the properties
q_1 > -1, q_1 < x
whenever
32
I.
PARTIALLY ORDERED SETS AND SYSTEMS
x>-1;
q2 < 2, q2 > y
whenever
and let
S2
1
consist of
y < 2.
alone.
Then
Let
S1
consist of all
x < 1,
V S 1 - V S 2 = 1, V S =» q2 < 1 + 1,
A s _ = q1 > - 1 • (6 .9 )
COROLLARY.
If
P
is a Dedekind-complete par
tially ordered group, the operation ous on P)
P x F
is also
to
P,
+
is
and the function
o-continu-
(-x : x
in
o-continuous.
This follows at once from (5-7)* $ 7*
LINEAR SYSTEMS, MULTIPLICATIVE SYSTEMS AND ALGEBRAS WITHIN PARTIALLY ORDERED SETS
As usual, by introducing an operation of "scalar multiplication" in a commutative group we produce a "linear system."
We shall always use
the real numbers for our scalars. (7-1)
DEFINITION.
A system consisting of a set
objects, a binary operation
+
P
of
and an operation of
scalar multiplication, Is a linear system If
(F,+)
is
a commutative group, and also: (
i)
To each real
a
and each
a
in
P,
there
corresponds a unique scalar product, de noted by
a a or
act; and, for all real
a,p and all a,b (a + p) a = ota + p& ,
numbers ( ii) (Iii) ( (
a(a + b)
iv) a (/3a) =
in
P,
= ota + ctb , (a/3)a ,
v) 1a = a .
It follows readily that
(-1)a = -a
and
Oa » $
for all
a
F. To define a linear system embedded in a partially ordered set, It remains to relate the operations to the order-relation. (7 .2 )
DEFINITION. A linear system F+ is a linear system embedded in a partially ordered set F If (a) (F+ ,+) (b) if a
a y_ 0 If
F+
is a group embedded in P, and is in F+ , and ot is real, and and
a > 0,
coincides with
then P,
act > 0 .
we say that
P
is
in
7-
ALGEBRAS IN PARTIALLY ORDERED SETS
33
a partially ordered linear system. The following theorem is an obvious corollary. (7 .3 )
THEOREM. system, and and
a
F
is a partially ordered linear
is a subset of
F
having a supremum,
is a positive number, then the set
Goia: a
in
{-aa: a (7 A)
If S
S)
in
has supremum
S)
THEOREM.
«(VS),
has infimum Let
F
and the set
-cc(VS) .
be a Dedekind
of
F.
-complete par
a
tially ordered linear system, and let
a
be a member
Then the following three statements are
equivalent. (
i)
o-lim n ^ a
exists,
n —* 00
( ii)
o-lim n ”1a n — > 00
(iii)
a
exists and is equal to
0
and
0,
have a common upper or lower
bound. If (i) holds, by (3-1), (3-9) and (7-3) we have o-lim n ”1a = o-lim [(2 n)” 1 a] = o-lim n" 1 (a/2 ) = 2 ~ 1 [o-lim n“ 1 a] , so (ii)
holds. If (ii) holds,
let M,N
(3-1)-
Let x
let n
integer
such that
0 < nx,
establishing (ill).
be in
N,
and
n “1a ,
V
or
A,
supremum, it shall be with reference to
or
thewords
>, never
». POSTULATES. (a) F is a [ a ]-complete and infinitely distrib utive lattice under the partial ordering >. (b)
»
(c) G
is a strengthening of
>
(cf. (1 •3 )) •
is a Dedekind complete partially ordered
set, such that for each two elements 36
with
of
G,
in
G
8.
THE POSTULATES
if
g1
and
g2
37
have an upper bound
they also have a lower bound in
G,
and vice versa. (d)
IQ
is an isotone function whose domain is a
subset (e)
E
of
tained in
G•
E
[countable] subsets
directed by
having
», «
V S 1 > A S 2,
V I q CS.j )
and
inequality
A l Q (S2)
VIqO
respectively and
and such also that
j)
exist in
> A i 0 (S2)
G,
the
holds.
If e1 and e2 are in E, and I0 (e^) and IQ (e2) have a common upper or lower bound in G,
there exist elements
such that (g)
and whose range is con
For each pair of
(f)
F
e* «
e^ «
e'
and
e”
of
E
e", i = 1, 2.
If 6*1^2 and e3 are in and IQ (ei) and IQ (e 2 ) Lave a common upper or lower bound in G, then for every f in F such that E
f »
mid(e1,e2,e^)
such that
f »
there is an
e
e >> mid(e1 ,e2,e^);
in
and
dually. REMARK. (6 .7 ) •
(8.1c) holds when
It clearly holds if
particular when
G
G
I
is a partially ordered group, by
has a greatest and a least element, in
is a complete lattice.
We now list some easy but useful consequences of the postulates. (8.2)
THEOREM. (a) (b)
If (8.1
for each
e
[.*)) holds: In E,
such that
there exist
in
E
e •«
e «
if
e 1, ..., en are elements of
e*
and
E
such
e”
e";
that each pair ^ 0 ^ei-1 ^ *^o^eI ^ 1x8,8 an upper or a lower bound, there exist e* and e"
In
(1=1, (c)
If
E
such that
e* «
e^ «
e”
..., n);
e1, e.j 1, ..., en , e*
such that the
I0 (©^)
are elements of
E
have an upper or lower
bound, and e^ > e ^ »
and the set of three elements IQ (e2)> also true. For (a) holds for
we take
n = 2.
is bonded.
e1 = e2 = e
I (e^),
The dual is
in (8.if).
Assume it true for
e^
e^, i = 1, 2;
By
(8.1 f ) statement(b)
n =*k - 1, and let
e1, ..., ek
satisfy the requirements of (b) . By hypothesis there are elements e" 1
such that
ments and
e2 *,e2”
e^ «
< < 6 ’^ (i - 1, ..., k-1),
such that
e2 *
and
I0 (©2 ),
(8.1 g) holds:
LEMMA.
(8.3)
If (8.1 [ e2; S* being directed, there is an element e* in S* such that e* » e 1 1 and er »
ed *;
and finally there
is an
e in SQ131Y ^ such that Up
e »
e* . The
proofs of the other statements in (b) are similar. (1 0 .3 )
Let (8.1[a]) hold.
COROLLARY. are summable and
U-elements, and
S2,..., Sn
are associated with
respectively, there exists a set u1
such that if
The set
is an
e »
e± , i = 2, ..., n.
Let
S1
(10. 10
u 1.
e-j_in
exists aset e*
Let
S in
e
is
associatedwith S
If
u
is an upper
and (10.1) applies.
of elements Then
... «
formed by (10.1) from
S1
and
e* »
e 1,
\/S2 < u. S2;
then
u
is a sum
e «
u,
there
and such that for
be any set associated with S2
e.
u.
By repeated use of
e2,...
of
Let
be the set
e1 »
S e
E
for all
such that e*
in
S,
V ( V S 1 , V S 2 ) = u.
(10.5)
THEOREM. summable
Let (8.1 [cr]) hold.
U-elements and
summable For By (8.1c) and
each
If
u^, . .., uR
I1 (u^), . .., 1 ^ (un )
common upper or lower bound,
which is
I 1(u1)
and
it is true that
u.
VS =
Then
in E
(8.2d) we select a set
and
such that
i = 1, ..., n,
e «
e2«
associated with
Let (8.1 [a]) hold.
COROLLARY.
e 1«
u 2, ..., un
has the desired properties.
mableU-element and every
..., uR
in S2, ..., SR
e in S
be associated with
I0 (e^) S = SSUp
S
e2, ..., en are
respectively, there
bound for
If
u 1 > u^ (i = 2, ..., n ) ,
are
have a
A (u1, ..., un ) is a
U-element. u •,
let
S(uj)
be associated with
, ..., I-| (un )
(6.7), the elements
also an -upper bound for
IQ (ej), e.
in
S
u •, j = 1, ..., n. have an upper bound,
j= 1, . .., n.
So
construction (10.1) can be applied to define Sinf. By (10.2), V S irrp = A (u1,..., un ), so this is a U-element. Being < u 1, it is summable.
(1 0 .6 )
THEOREM.
Let
K
be a [countable] collection of
kk
II. summable
DEFINITION OF THE MAPPING
U-elements such that for each pair
elements of
K, I 1(u1)
and
upper or lower bound. For each finite subset that
u
in
K,
u 1, ..., uR
I1(u2)
Then let
VK
is a
S(u)
of
U-element.
be associated with
of elements of
I1(u1), ..., I1(un ) have
u^,u2
have a common
K,
u.
For each
by (8.1c) and (6.7) we see
an upper bound.
So we can apply (10.1)
to
the sets
S(u.), ..., S(uII) to construct Sa___. I o Lip Let S be the union of all the sets S3Up thus constructed. [Then S is countable]. If e^ and
e1 *
are in
S,
we can find two finite sets
u 1, ..., un
and
U 1 *9 ^m* elemerrts of K and elements e 1, ..., em * of ..., S(‘um r) respectively such that e « V l e ^ •••> en ) and e* « S same element as now
S
em ,^‘ ^ an^ U 1 ^-s also an u j ,, we can clloose the e^ and e j f> since the S[u] are directed by » . But
contains
directed by» . VS(u) = u.
e*In
S
e
in
(10.7)
e 1, . .., eR , e ^ 1, ..., em f,
Is a
such that S
eT »
e, K,
there are sets Hence
the U-element THEOREM.
U-element.
u in
of those sets such that
V {u1, ..., un ) < VK. is equal to
e" »
VS
This holds for all
hand, for each ei, ..., eR
an element Therefore
there is an
S(u1),
If
e
so
is in
so
V S > e,
so
V S > VK.
whence
S
is
S(u), VS >
On the other
S(u1), ..., S(un )and members
e «
V S < VK.
V ( e 1, ..., eR ) < This proves equality,so
VK
VS. Let
K
be a [countable] collection of
summable
U-elements directed by
summable
U-element if and only If the set I1(K)
an upper bound in
G;
>.
Then V K
and in that case
is a has
I1 (V K ) =
(K) .
I 1 (u), u
If
VK
in
K.
is summable,
I^VK)
is obviously an upper bound for
So I^VK)
:> Vlj(K)
.
Conversely, suppose there is an upper bound forI1(K) . Using the of (10.6),we construct the set S. For each e in S there are
notation elements
u v ..., un of K such that e V(u.j, ..., . Hence e « u, and IQ (e) < I1 (u) < V l 1 (K) . VS Is a summable U-element, and also
Then by definition
I1 (VK) = I 1 (VS) = V l I Q (e): e < Vl^K)
.
in
S)
VK =
11. DEFINITION OF THE MAPPING OR INTEGRAL
^5
The reverse' inequality was established above, so equality holds. (10.8)
THEOREM. are
Let (8. [cr]) hold.
U-elements and
mid (u1,u2 ,u^)
u 1 < u2 ,
If
and
is a summable
u 1, u 2
u2
and
u3
is summable,
U-element.
Let S 1 and be sets associated with u 1 and By (10.3), there is a [countable] subset S2 of E
tively. X>
having
V S 2 = u2 ,
e2
in
for which
S2
and such that for each e2 »
e1 .
So
summable
mid (u1,u2,u3)
in
S1
there is an
Then by (10.1) we can construct
This is [countable and] directed by (10.2).
e1
u^ respec directed by
is a
»,
and
V S mld = mid ( u ^ u ^ u ^ )
U-element.
Since it is
< u 2,
by
it is a
U-element. $ 1 1 . DEFINITION OF THE MAPPING OR INTEGRAL
Again we shall assume (8.1) or (8.1a) to be satisfied. frequently need to refer to the set of all summable given
f
of
F,
We shall
U-elements above a
so we shall provide a symbol for this set, and also for
its dual. (11.1)
DEFINITION. of all summable L[< f]
LEMMA. L[< f] form
isin
F, U [>f]
u
is the class
satisfying
is the class of all summable
satisfying (11.2)
If f
U-elements
u > f,
and
1
L-elements
1 < f. Let (8.1 [cr]) hold.
If
f
is in
is not empty, the set of elements of 1^ (u) (u
in
U[> f])
is directed by
F
and
G
f]
suchthat
1^1) < g-|,g2 * clearly
g1
> f,
and
g2 are in the class, there areelements
g 1 = I1 (u1)
So by (10.5), so it is in
and
g2 = I1 (u2) . For
u 1 A u2
U[> f ]•
both
any
1
in
(i = 1 , 2) .
DEFINITION. If f is an element of F such that U[> f] and L[< f] are non-empty, we define the
upper and lower integrals [or images] of respective formulas
f
of
L[< f],
U-element, and it is
Also, by (9 -5 )
I 1 (u1 A u 2) < I1 (u±) = (11 .3)
is a summable
u^,u2
by the
k6
II.
DEFINITION OF THE MAPPING 1(f) = Al,(U[^ f]) , 1(f) = VI, (L[^ f])
These surely exist; for if L[< f],
-chen
I^u*)
lover bound for
ur
•
is in
is an upper bound for
I, (U[> f] ),
U[) f]
1'
and
I1 (L[^ f])
and
in
I (lf)
is a
and by (11.2) and (8.1c) the right members of
the above equations exist. If former Is Thus
IT[> f]
>
I 1 (u)
L[< f] 1
I 1 (u) > 1 (f),
Then
so must be
f]),
and
each element
I1 (L[< ?]) > and
its infimum,
1(f)
of the
must be
>
its
1 (f)
isa lower bound for
1 (f).
So:
Let (8.1 [a]) hold.
and
u
I1 (u) > 1 ^(1 ).
If
f
is in F,
exist, they satisfy the relation
1(f) < 1(f). Another corollary of the definition is the following: (1 1 .5 )
Let (8.1 [a]) hold.
THEOREM. in
P
If
f1
and
fg
are
and both have upper and lower integrals, and
f 1 < f2 ,
then
T ( f . ) < T ( f 2)
For then
U[)> f 1 ] ^ U Q
f2],
and so
K f , ) < Itf,).
I1 (U[^ f 1 ]) => I1 (U[^ fg]),
the former set has the smaller infimum, that is
Iff^ < I(f2) .
The other
conclusion is established analogously. (11.6)
DEFINITION. ment of
F
Let (8.1[a]) hold.
for which
1 (f)
and
If
1 (f)
f
is an ele
are defined and
equal, we define the integral, or image, of 1 (f) = 1 (f) = 1 (f).
In this case
f
f
to
be
is called a sum
mable element. We have already used the adjective "summable" in (9 -1 ); so we shall show that there is no contradiction between the two uses. (1 1 .7 ) is a
THEOREM. Let (8.1 [a]) hold. If f is in U- or L-element, it is a summable U- or
P and L-ele
ment as defined in (9*1) if and only if it is summable as defined in (11.6). In this case 1 (f) = I.,(f). We consider
U-elements only; the case of
and
L-elements can be
11. DEFINITION OF THE MAPPING OR INTEGRAL discussed dually.
Suppose first that
sense of (11.6). exists a For all Thus
U-element e
in
I0 (S)
f is
Then there is a set u
a
l*-7
U-elementsummable in the
S associated
with f,
and there
summable in the sense of (9 -1 ), such that
S we have
e «
VS = f
f] contains
f
is a summable f.
L-element itself, so
in
S, by (9 *7 ) there is a summable
so
I0 (eQ ) < V l ^ L K
f]) = 1 (f).
eQis in
«
eQ ,
f
1
then
L[ 1Q(e^ + I0 ^e2 ^ whence I 1(u1 V u 2) + 11(u1 A u 2) 2, (u i) + I-| (u2) . This completes the
§ 1 3 - LATTICE PROPERTIES OF THE CLASS OF SUMMABLE ELEMENTS
Postulates (1 2 .1 [a]) are not sufficient to cause the class of summable elements to be a sublattice of
F.
However, we can establish some
closely related properties. (1 3 .1 )
THEOREM. Let (12. 1 [
f^
are summable and that
U-elements such that also a summable
mid (u1A u 2,u2 ,u^)
(10.8),
f 1.By
and
u^ ^ f^,
U-element, and
is a summable 1^
and it
is clearly > mid (f1,f2 ,f^).
i = 1,
2, 3 , mid (1 ^,1 A.t ) I I, V L C J is a summable L-element and is > Thus the upper and lower integrals of mid (f1 ,f2,f
mid
Likewise, if
U-element,
is in
L[
f 1 ]
I1 (u^)
and
and
u2
in
U[^ f2 ].
so by (1 2 .4 )
I1(u2),
By the preceding proof,
f 1 V f2 **
f 1 A f2 is summable.
Similarly,
be any three summable elements such lower or upper bound. Then
f 1 V f*2
f1 A
f*2 are summakie > and first part of this proof mid (f^ A f2 ,f1 V ?2’f^ is summable. By (2.13), this is the same as mid (f1,f2,f3) . (13.2)
THEOREM. and
f2
and
I(f2)
f 1 A f2
Let (12.1[a]) and (12.7) hold.
are summable elements of
F
have a common bound, then
such that f ] V f2
are s-ummable, and
Kf,V f2)+ i(f1 A f2)= i(f1)+ i(f2)
If
f1 K f^)
and
that and
14.
We already know that ^
belong to
U[^ f ^ ,
U [ > f 1 V f 2i
and
f 1 V f2
I = 1, 2.
u,Au2
in
f 1 A f2
and
Then by (12.8),
A f 2l,
U[) f,
I(f, V f2 ) + I(f, A Since
55
MONOTONE SEQUENCES OF SUMMABLE ELEMENTS
f 2)
is an arbitrary member of
are summable. V
Let
Is In
and
< I,(u,) + I,(u2) .
U[^ f^],
this implies
I(f, V f 2) + I(fl A f2) < I(fl) + I(f2) ' The reverse inequality is obtained by considering elements of i = i, 2,
L[< f^],
which completes the proof. As an aid in verifying one of the hypotheses in the two preceding
theorems, we establish a lemma. (13.3)
LEMMA. f1
If
andf2
E
is directed by
are summable, then
>
or by
Kf^)
and
f^] e
and
e^ «
u^
satisfying either
e < e^ (i = l, 2).
Hence
lower bound in
by (6.7) they have a common upper bound.
G;
IQ (e1)
and
e = 1, 2.
I0 (e2 )
consecutive elements of the finite sequence I^Ug), I(f2)
has an upper bound in
G,
By hypothesis,
e > e^ (e - 1, 2)
or
have a common upper or Each pair of
I(f.,), I 1 (u1), IQ (e1), IQ (e2)>
so by (6.7) all six have a common
upper and lower bound. 4 14 .
MONOTONE SEQUENCES OP SUMMABLE ELEMENTS
In order to establish convergence theorems of adequate strength, we apparently need
to add something to postulates (12.1).
Theconvergence
theorems will rest on theorems concerning monotone sequences, and in this section we establish two such theorems.
The first is of less general
applicability, but is not entirely without interest. Our first strengthening of (12.1) is as follows. (1L.1)
POSTULATE.
G
is-a group under
+
with the
property that whenever S 1 , S2, ... are countably many subsets of G directed by < and having A s ^ = 0 for
1=1,
2, ...,
it is possible to choose elements
g-l > g2> ••• such that g^ is in Si and the sums g 1 + ... + g^ (k = 1, 2, . ..) have an upper bound.
56
III.
CONVERGENCE AND MEASURABILITY
For example, the reals have this property; but the group bounded
real functions on an infinite domain
D
of
lacks the property, as we
see if we take each S^ to consist of all the functions which vanish on finite subsets of D and are 1 on the rest of D. (14.2)
COROLLARY.
and (1 4 .1 ) hold.
Let (12.1[a])
S^
S2, ...
by
fQ],
and so
Sj + 8 •
J
By (1 4 .2 ) and (6 .8 ),
T(f0 ) i g • On the other hand, since I(fn ) < I(fQ ) , Hence
so
f
< f
for all
n,
g = lim I(fn ) < I(fQ ) .
is summable, and I(f0 ) = g = lim • The somewhat restrictive requirement (1^.1 ) can be replaced by the much weaker assumption of normality of G (cf. (5 *9 )), provided that we strengthen the hypotheses on the sequence (fn : n = 1 , 2 , ...): (A.M
fQ
THEOREM.
Let (12-1 [cr]) hold, and let
G
be
a
58
III. normal.
CONVERGENCE AND MEASURABILITY'
Let
f 1,f2, ...
be an Isotone sequence of
summable elements such that there exists a summable U-element Let
f
u
1(f) =
which satisfies
11m fn . n — >oo
=
llm
Then
u > fn , n = 1, 2, ... .
fQ
Is summable, and
I(fn).
n —> oo As before, we define _ 1(f)
g
are defined, and by (11-5) For each
U
fn ] and
l'n
to be
llm fn n — > oo 1(f) > g-
n,
the elements
in
L[ f ] SI II
1* II
and
in L[< f„] 2S. H
so that
(*)
CMu'O
J-1
- I1(11_j)] + g) < r(g) + €
J
for all positive integers
n.
J Without loss of generality we may assume
u *n ^ u **or each n > since we may replace u*n by u'n A u . Next we define un - Vtu'j, u'n ), ln - Vll'j, ..., l'n JThen
uR
is a
U-element by (10.6), and is
summable because it is < u;
and
1
^
fn < un (n = 1’ 2 ’ ••’J* As in the proof of (1U.2), by induction we prove
is asummable
W Since
r
S
2
L-element by the
;
,
dual of(10.5).
[Ii(u’n> -
is isotone and
+ W
■
this implies
^
r(I l(un ))
Uj > f . for each
since fore in
U[^ fQ ] .
Since
r
j,
59
It is summable, being V nun ^ V f j = fQ ,
< u;
and
and it is there
is smoothly rising and consequently Is
o-continuous, r ( I , < V n»n »
- V nr(I,(»n )) < r(g) + € •
But
V nun
is in
U[> fQ ],
so
1 ^ V nun ) ^ I(f0),
and
r(I(f0)) < r(g) + € .
e
Since
Is arbitrary,
r(I(f)) £ r(g) . Here
so by the normality of G (cf. (5 *9 )) previously established inequality 1(f)
r
Is any member of
R^,
1 (f) < g. With (11A) and the > g, this implies 1(f) = 1(f) = g,
and the proof is complete. It would seem reasonable to expect that the hypothesis of the existence of a summable have an upper bound in
u > f G.”
by the following example. [0,1],
G
F
could be weakened to read "the
consists of all extended-real functions on
of all (finite) real functions on
functions on
[0,1].
is the same as
>.
The partial order > IQ
I(fn )
The impossibility of such a weakening is shown [0,1],
E
of all continuous
has the usual meaning,
is the identical mapping.
We find that
and u is
» a
U-element If and only if it is lower semi-continuous and bounded below, and dually for
L-elements; a
U- or
L-element is summable If and only if it
is finite-valued. Now let the rationals In sequence
t1, t2, ... ,
1 = 1 , ...,
and to be
and let 0
f
elsewhere.
[0,1]
be arranged in a
be defined to equal Each
f
I
is a summable
at
t^,
L-function,
and I(fn ) = “ ^n * The supremum of I(fn ) is the element f, defined by the equation f(t^) = I (i = 1, 2, ... ), f(t) = 0 elsewhere. But ment
V nfn
is not summable.
u > V nfn -
This
u
If It were, there would be a summable
U-ele
Is lower semi-continuous and finite-valued, but
Is unbounded on every interval.
This contradicts a well-known property of
semi-continuous functions. § 15.
DOMINATED CONVERGENCE
The results in the preceding section allow us to establish a generalization of the Lebesgue dominated-convergence theorem. (1 5 -1 )
THEOREM. Let (12.1[a]) hold, and let G be normal. Let (f(a):a in A) be a net of elements
60
III. and
f
CONVERGENCE AND MEASURABILITY
an element of
A
with the following
properties. (
i)
For each
C il)
a
in
A, f(a)
is summable.
There exist summable elements F
such that
In (iii)
f 1 < f(ot) < f"
f^f"
of
for all
a
A.
The net
(f(a):a
vergent to
In
A)
is
I0 (eQ ).
e* » If
eQ ) e*
is di
Is in
S',
15. by (9 -7 ) there is
a
DOMINATED CONVERGENCE
U-element
u*
such that
63
eQ «
u» «
e* . Then
£ I i(u ^ i Io (e')' 30 T(eo) ^ V e>)- 811(1 because e * is an arbitrary number of S 1, i(e0) ^ A l 0 (S*)« Dually, if S is the set {e: e
in
E
and
e «
eQ ),
then
I(eQ ) ^ V l Q (S) " A I
q
CS1),
V l 0 (S) < I0 (e0 ) • These inequalities establish the conclusion.
and also If
»
is
reflexive, both S and S* contain eQ , so A l 0 (S') = ^o^o^ = V l Q (S), and as just proved this establishes that I(©Q ) exists and is equal to w
• We now return to sequences of functions, and establish some easy
theorems, the last of which is a generalization of Fatou's lemma. (15.7)
THEOREM. Let (12.1 [a]) or let (1^.1 )hold.
If
hold.
S
i(As) = A
k s
f*,
then
^
and
As
1, 2, ...),
the conclusion holds by (15-2).
such that
A nfn = A s .
THEOREM. Let (12.1 [ fj > f», (j *
Let
G be
normal,
is a countable set of
sum
>
f*,
a summable
element
is summable.
S*
are summable.
S*
f, f 1, f2 , f^, ....
such that
fR > f (n =
by
By (13.1)
f2 > f^ > ...
S
As
S
).
By (2 .^0 , there is a sequence
then
normal,
is summable, and
elements of
(1 5 *8 )
G be
is a countable set of
summable elements directed by mable lower bound
Let
Then
fR )< g*;
lim inf fn
is sum
in particular, if
then I(lim inf fR )
m
we have
Kf-^) < g»,
and
6k
III.
moreover f*21 ^
CONVERGENCE AND MEASURABILITY’
I(fm 9) ^ lim inf I(ij)
•••f ty (1^. 3 )
if* this last exists.
V m?m ' is summable, and
and KN/jn^jn') < lim infn I(f*n ) so the proof is complete. §16.
Since
K V / ^ )
if this exists.
f1* ^
= V ^ K ^ ' ) ^ g»,
V m?m ' “ lim inf fj,
But
STRUCTURE OF THE SET OF SUMMABLE ELEMENTS
The information about summable elements obtained In the preceding sections can be combined into a theorem on the structure of the set of summable elements of
F.
Recalling the discussion following (6.7), we note
that each element
of
G
all elements
g*
g
determines a subset
such that
g
and
g*
GCT of G consisting of o have a common upper or lower
bound; two such classes are either disjoint or identical, and each is in fact a coset relative to the invariant subgroup
G^•
Correspondingly, we
adopt a notation. (16.1)
DEFINITION.
Let (8.1[a]) hold.
F gun]
to be the set of all summable elements of g
in
G,
F
such that (16.2)
For each
is the set of all summable elements
1(f)
t THEOREM. Then
is defined F.
is in
f
G . o
Let (8.1 [cr]) hold and let
G
be normal.
F gum is the union of disjoint classes
F^
with
the following properties. (
i)
If
f,ff belong to distinct classes
F ,,
the pair
{f,f *3
upper bound nor a lower bound in ( II) (Hi)
F ,
has neither an F gum.
F sum is Dedekind o -complete. Each class Fg is a conditionally
-com
plete lattice. (
iv) If (1 5 *^) holds, for all IQ (e)
( (
v) I
Is a
e
in
If and
f
I(f')
F_,l rri contains oUIu the equation
E,
(t o -
00 *-continuous
continuous and
map of F gum into G. vi) If E is directed by > or by is only one non-empty class F^,
and
f* F . o
f" ].
changes, shows that
mid
= mid (f^f" *niid (f1,f2 ,f^)).
(13-1) and (17*3) it is sufficient to prove that
So by
mid (f1,f2,f^)
is
summable. Let
S ^
(i = 1, 2, 3)
the first directed by
«
be three [countable] subsets of
and the other two by
»,
such that
E,
A s ^
=■
f -, V S (2^ = fQ, V S (3) = f,. For each pair e ^ and of elements i /j \ fi 1 (i) of S^ ; such that e; ; « e^ ;, we choose exactly one U-element and (!) (i) exactly one L-element between e : ' and e;, this is possible by (9 *7 ) (i) The chosen U-elements form the set S^j ' : the chosen L-elements form the set and
S-^ .
u, A u 0
(2.13),
If
u 1 ,u2
S^1\ S^2^ respectively,
are in
are summable
U-elements by (12.4 ) and (10.5).
mid ( u ^ u ^ u ^ ) is a summable
U-element whenever
(i = 1 , 2, 3 )-
Likewise, whenever
1^
mid (l^lo,!,)
and
are summable
Let tively.
mid (f-,l0,lx)
3
i
is in
(i = 1 , 2, 3), both L-elements.
("i)
X 1,l2,l^ be arbitrary members of
(2)
, S^
S ^
(i = 1, 2, 3)
exist elements
^ 2^ 3
wlth
such thatu 1 < X 1 ,u2 > l ^ u ^ > I3 X^
in
S^1 ^ such that
respec
< f2 ^ 1 2 ,
Since
it follows that
mid (fn,1 2,1 ^)
I 1(f2),I1(f1),I1(mid is in
and
L[^ mid
f2, so the ele
f 1 £ mid ( f ^ f g , ^ ) , (f 1 ,f2, f ],
)> f 1 ,
by the distributive
law
[mid (f 1,x2,x^) ]\/x1 = [(f, V
X 2)
.
A(f,V ^ 3)/\ (X2V ^ J I V X ,
= (X, v V A t x ,
V * 3M
> mid (X1,X2 ,X5) . Hence, using (12.6),
G.
so
and
I1 [mid ( f ^ l g , ^ ) V f ^ £ I[mid ( f ^ f g , ^ ) ] X
Then
.
have a common bound in
mid (f1,l2 ,l5) £ mid (f 1 ,f2,f^) [mid (f 1 ,12,15) ] V f 1
and- there
X^ > ui -
mid ( f ^ l g , ^ ) < mid ( u ^ ^ , ^ ) < mid ( X ^ X ^ X ^ )
Since
(i)
By the manner of definition of these sets, there exist elements
in
ments
u.j V u2
By (10.8) and (i) u^ is in S^ '
(xi \ A 2 \ A 3)
Also,
17 • MEASURABLE ELEMENTS
67
I 1 [mid ( u ^ u ^ ) ] < I 1 [mid (X1,X2 A 3 )1 < I, [mid (f,,X2 ,X3)yX,] < I 1 [mid ( f ^ X g . ^ J V f , ] + I^X,)
- I, (f,)
< I [mid (f,,f2,f5 )] + I,(X,) - I,
(mid ( u ^ U g , ^ ) : u2
and has
mid ( u ^ f g , ^ )
ln
(2)
Sg }
as supremum.
and
u^
ln
Hence by
( 1 0 .6 )
I1 (mid (u1 ,f2,f3)) < I[mid ( f ^ f g , ^ ) ] + “[I1(X1) But
mid(u1,f2,f3)
is
ln
.
U[> mid ( f ^ f g , ^ ) ] , hence
I (mid (fv f2 ,f3)) < I[mid ( f ^ f g , ^ ) ] + [I1 (X,) - I1 (f 1) ] . The set of values of the quantity in brackets corresponding to all S^^
has infimum
0,
I [mid ( f ^ f g , ^ ) ] < I [mid ( f ^ f g , ^ ) ] This proves that
I[mid ( f ^ f g , ^ ) ]
in
If
(f(o)sa
is a net of measurable elements and is convergent to a limit
.
exists, and the proof is complete.
THEOREM. Let (12.1 [a] hold.
(17-6)
X1
so by (6 .9 )
fQ
in
F,
in
>' ,E' ,G' ,I0 ‘)
(P, » ,
E,G,IQ )
and
be two systems satisfying (8.1 [
is an
fl-summablllty may be ignored, because
subset by using only satisfy
I*-summable
I-summable element of
^ ( u f)
greatest element and all U*[f*]
V ^ 0 (S')
- \Zir\IQ '(e1)): e*
* Vl^^CS'))
r(I ^1(u* 1)) . The dual holds for Now let f*
SO
71
I(J>(f))
and
I(4 (f'))
I(£(f *)) ^
I*(f*) is
also in
r(I* (f •)) .
It follows
both exist and are equal to
and (iii) is established. Finally, suppose that
9Q
I — summable and is ln the domain of U-element such that directed by »
u* ^ f 1,
andhaving
and the set consisting
off'
is smoothly rising and that
,Qq . Let
and let
S'
u*
be any
f•
is
I — summable
be a [countable] subset of
V S ' = u * . Because alone is directed by
issmoothly " ^i(u ') • r ^Cie discussion in the preceding paragraph remains valid with 0o (f') in place of $(f')> and shows that K t f ^ f 1)) ^ r ’d'ff*)) and
I(^^Tf*)) ^r(I'(f')).
r( 1 1(f ')).
Hence
$Q (f)
is
I-summable, and
I($0 (f) *
This completes the proof.
h.
summable. Let
e2 in S2
-
g < h,
U-element
e1 in S 1
(-mid
,f))]
/ \ [ \ / mid ( e - ^epSf)] -e2 * in S2 -e1 1 in S1
= - mid (-l,-u,f) , which is summable by (19-3) and the definition of measurability. (21.2)
THEOREM. satisfied. longs to
Let the hypotheses of Theorem
Let
f
(19-1*) be
be a measurable element which be
F+ ,and let
c
be a real
number.
Then cf
is measurable. As in the preceding proof, we need only show that is summable when and
u > 1.
Let
S^,S2
1
is a summable
(c^e: ein
L-element which we call
mid
u
mid (l,u,cf)
a summable
Also, by virtue of (21 .1) it is enough to consider -i be associated with l,u respectively, and let c
set we call
L-element and
u_, c
S^)
= 1, 2 ).
(e
lc , and
Then
V c ~ 1S2
U-element c > 0. be the
A c ” 1S l is a summable
is a summable U-.element which
and
(l,u,cf) =
\ /
[
e2 in S2
mid (e.,e2,cf)]
/ \
e1 in S 1
\ / 1 t / \ e2 • in c S2 e 1• in c = c
\ / e2 * in c
1 mid (ce- • ,cep »,cf)]
S1
[ S2
mid (e»,e »,f)] e^
in c
S1
- c mid (lc ,uc ,f) . This last is summable by (1 9 .^). To establish the measurability of the sum of measurable elements
21 .
OPERATIONS ON MEASURABLE ELEMENTS
79
it seems at least desirable and probably necessary to add a hypothesis, assuming a strengthened form of normality for
P.
Let us first introduce
a definition.
(21 . 3 )
DEFINITION.
If
tially ordered set
F+
P,
is a group embedded in a par
Rp +
is defined to be the set
of all smoothly rising extended real-valued functions on
P
which are finite on
tion
are in (21 .10
F+
and satisfy the equa
r(f1 + f2) * r(f.j) + r(f2)
whenever
f1
and
f2
F+ .
THEOREM.
Let the hypotheses of (19-M*]) hold.
Assume further ( i)
if
f.j
P,
there exists a function
and
such that (ii)
if
f
F+ ,
so is
r f
are distinct elements of
r(f1) ^ r(f2),
is in
all Then whenever
f2
in
P
and
Rp + ,
and
g
r(f)
then
r
in
f
is finite for is in
u
f + g.
a summable
mid (l,u,f + g) 1
and
u
U-element and
is summable.
respectively. Let
e * - ( e " - e ') - ... - (e " o 1 1 m S* and e^', ..., em "are in of
the form
are in
S”
e0” + (e^1 - e ^ ) and
e^,
..., en *
We easily verify that and that mable in
1^ s A & m *
U-element.
SM ,
for each
Let
S'
Rp +
and
SM
1
is a summable
the element
be sets associated with
- e •), where e •, e » , ...# , e • are in m 9 o 1 7 m S"; let Sn" be the set of all elements + (enfl - en *)> where are in Sm *
is a summable in
1 < u,
Sm ' be the set of all elements of the form
e0", e ^ 1, ..., en"
S f.
is directed by
« and
L-element and s V s nM
Also', if eQ ', r
F+ .
are measurable members of
As before, it is enough to show that when L-element and
R„ ^ r ,+
and
em '
are in
S*
and
Sn" by
»,
is asume^n ,
..., em"
we have
r(e0 » - [e1M -©-,•] - ... - [em” - em #]) - r(eQ ) - r ( e }") + r(e1 ') - ... - r(em ") + r(em t) , and since
r
is smoothly rising this implies that r d m ) - r(l) - m[r(u) - r(l)] ,
where
r(u) - r(l)
Likewise
is
^ o and may be
r(un ) » r(u) + n[r(u) - r(l)]
+ »,
in which case
r(lm ) * - ».
80
IV. We now define
r
ALGEBRAIC OPERATIONS
fm>n = mid ( l ^ u ^ f ) ,
- mid ( l ^ u ^ g ) .
Since
is isotone,
p(fm,n) and analogously for r(ln )
be
+ oo,
hypothesis,
n ) • But
and r(f)
f ■
Since
is in P
For
r
F+ ; andsimilarly, so is
and
n
lim ( lim [r(fm n ) n —> oo m — > oo 9
r(fm
n-
+ rfg^ n )]) . 9
If
r(u) - r(l) > 0,
r(un )
> r(g) > r(ln ) ,
for all
we have
r(uR ) > r(f) > r(ln ) so
By
we have
We now distinguish two cases. m
nor can
lim ( lJjn t f ^ n + g ^ n l ) n —> oo m —>oo 9
+,
r(s) -
large
- oo,
r(fm n ) isfinite.
is a complete lattice, the limit
in Rp,
(*)
r(un ) can never be
is finite, so
s =
exists.
(!*(!„,)'r(um )'r(f 5} ’
n)
=
r(f)
and and
* ( 8 ^ ) = r(g) •
Thenby (*)
we
r(s) - r(f) + r(g) - r(f + g) , whence (**)
r(mid (l,u,s)) - r(mid (l,u,f + g)) .
If ©n the other hand
r(u) - r(l) * 0,
all real numbers
and (**) continues to hold.
r
in
R™
r ,+
.
z,
then
mid (r(u) ,r(l) ,z) - r(u)
for
Thus (**) holds for all
whence mid (l,u,s) = mid (l,u,f + g) .
But lim 11m mid (l,u,f m — > oo n —> oo 9
+
) 9
- mid (l,u,s) , and the elements and
u.
mid (l,u,fm n + ^
Hence by (15*1)
summable, and
f + g
mid (l,u,s)
is measurable*
n)
are summable and are between
is summable; so
mid (l,u,f + g)
1 is
find
C H A P T E R
V
REAL-VALUED FUNCTIONS
$ 22.
INTEGRALS OF REAL-VALUED FUNCTIONS
An important special case of the preceding theory is that in which and
F
F+
consists of all extended-real-valued functions on a domain consists of all (finite) real-valued functions on
T,
the defini
tion of order, addition and multiplication being the standard ones. sets
F
and
F+
satisfy all the requirements placed on sets
in preceding theorems, so (with appropriate hypotheses on all preceding'theorems are available. G
F
G, E, IQ ,
G.
Accordingly, we assume the following
postulates. POSTULATES. (a)
F
consists of all extended-real-valued func
tions on a domain on t (b)
F+
F, f 1 ^ f 2 in
T;
means
and for all
f 1, f2
fj(t) > f2 (t)
for all
T.
consists of all (finite-) real-valued
functions on F+ , fj + f2
T;
if
f1
and
f2
are in
is the function
(f1(t) + f2 (t): t
in
T),
andscalar
multiplication and binary multiplication are analogously defined(c)
»
(d)
G
is a strengthening of
(e)
ordered linear system. IQ is an isotone function whose
is a normal Dedekind-complete partially
subset E tained in (f)
of G.
F
domain is a
and whose range is con
For each [countable] subset 81
F+ etc.)
We do not
to iDe the real number system, but we do wish to
perform linear operations in
(2 2 .1 [a])
These
and
However, one new idea enters, namely
the concept of a measurable set, and this we must investigate. wish to restrict
T
S
of
E
82
V.
REAL-VALUED FUNCTIONS
directed by IQ (S) (g)
If
e1
IQ (e2 ) G, (h)
«
and such that
is bounded below, and e2
are in
E,
there exist elements e' «
If
and
e1 ,e2
and
I (e 1) and
e.^ « e^
e*
and
e”
of
E
e", i * 1, 2.
are in
E,
and
I0 (e2 ) have a common upper or lower
bound in that E
and
have a common upper or lower bound in
such that and
As < 0
/\l0 (S) ^ > e »
f
in
F
such
there is an
e
mid ( e ^ e ^ e ^ ) ;
in
and
dually. (i)
Whenever and in
c2 E,
c 2 I 0
e1
and
e2
are
in E
are real numbers,c ^
and
c1
+ c2e2
is
and IQ (c1e1 + c2e2) = c 1IQ (e1) +
( e 2 ^ 5
e
8 ,1 1 (1
^
e
^
,
^
8 1 1 (1
e 2
*
a r e
in E and e^ « ei 1 (i = 1, 2) and c < 0, then e1 + e2 « e1 * + e2 * and ce1 » ce1 *. It Is obvious that if we assume ( 2 2 . 1 [a]) we at once obtain the conclusions of (19-3) and (19*^); and if we also assume hypotheses (I9*5d,e,f) we obtain the conclusions of (19«5)*
However, we can establish
stronger statements. As usual, let us define » + x ~ x + « > » « If x > - o o , - oo + x = x + ( - o o ) = - o o if x < + oo. Then we can define f 1 + f2 t
in
is F+ .
to be
(fj(t) + f2 (t): t
In
Tat which one of the values
- oo. + oo,
so
f2(t)
U-function is ever
f 1 + f2
U-functions or both (22.2)
provided only that there Is no
This agrees with the definition of +
In particular, no
ever
T)
fj(t),
- oo,
Is defined whenever f 1
«
and no and
and theother
f1
and f2
THEOREM.
Let (22.1 [a]) hold. Let
2),
and let
Kf^) s
and
f1
iCf^)
areboth
and
f2
are defined
be a function such that
s (t ) — (t ) + f2(t) whenever the sum Is defined, s(t) being arbitrary (finite, + oo or - oo) else where in
T.
Then
I( f ,) + I ( f 2 ) < 1(8)
£
1(8) < T ( f 1) + T(fg) ,
T(-f,) - -Kf,), K-f,) - -T(f,) • In particular, if
f1
and
f2
are in
L-function is
f2
L-functions.
be functions such that (1-1,
is
when
are summable, 3 0 are
22. and
83
INTEGRALS OP REAL-VALUED FUNCTIONS
-f,,
and
I(s) = K f , ) + I(f2 )
and
I(-f) =
-I(f,) If
la in
defined for all tively, then u 1 + u2
t
in
U[^ f± ] T.
(1=1,
S1,S2
If
u 1 + u 2 = V ( e 1 + e2 : e 1
is a
1),
then
u ^ t ) + u2 (t)
are associated with
S1 and
ln
u,,u2
e2
ln
S2),
and
e2
in
Is respec so
U-functlon and
I1(u1 + u 2)=
V ( I 0 (e1 + e2): e, ln
-
S,
S2 )
+ V i 0(s2)
V W
= I 1(u1) + I1(U2 ) . Whenever
f ^ t ) + f2 (t)
is defined, we have
s(t) * fj(t) + f2(t) < u 1 (t) + u 2(t) . Where
f ^ t ) + f2 (t)
Then
u ^ t ) is
+ * > s(t) .
isundefined, one summand
+ », while
Hence
u 2(t)
u 1 + u 2 > s,
cannot
be
(say
f^(t))
-
so u ^ t ) + u2 (t) *
is
+ «.
and
I(s) < I1(u1 + u 2) = I1(u1) + I1(u2) . This holds for all
u 1 ,u2
in
T(s) i
U[^> f 1 ], U[> f2]
Ai/uD
respectively, so
f 1 ]) + A i , ( u q f2 ])
= i(f1) + i(f2) . The statement concerning -f1
I(s)
is established dually, and those concerning
are easy to establish.
(2 2 .3 )
THEOREM. and 1(f) |fI
and
Let (2 2 . 1 [a]) hold. 0^
If
f
is summable,
have a common upper or lower bound,
is also summable and -I(If I) < 1 (f) < I(If I) .
For then by (2 2 .2 ) and (6 .7 ), I(-f), 0 q and 1(f) have a common bound, and by (1 3 -1 ) If I is summable. By (1 1 .8 ) the inequalities hold. t
in T)
For each fixed t in T, is smoothly rising on F
the function r^ = (r^.(f) * f (t ): and is finite and additive on F+ ,
so
Qk
V.
it belongs to
RF + .
REAL-VALUED FUNCTIONS
It is obvious that hypotheses (i) and (ii) of (2t.3)
hold, so by this and (21 .1) and (21 .2) we have (22.U)
COROLLARY.
Let (22.1 [a]) hold.
If
f1
c
is a real
are finite-valued and measurable and number, then REMARK. and
fj(t) + f
n
and
cf1
are also measurable.
This can be improved; if
f2 (t)
is defined for all
f2
t
f1
and
in T
fg
then
are measurable f 1 + f2 is
The proof is essentially that- of (21 .3 ); the chief change is
measurable. that
f 1 + f2
and
and
gm n
may not be finite-valued, but in any case their sum
is defined. Given any set
M,
we shall denote by
function, that is the function whose value is is
0
x^ 1
its characteristic
at each point of
M
and
elsewhere.
(2 2 .5 )
DEFINITION.
If
finite measure
if
the measure of
M
x^
M
is a subset of is summable,
D,
M
and
has inthis case
is
= I(xM) ; M
is
element of
the set
F.
a measurable set if x ^
If for a sequence
E 1, E 2, ...
is a measurable
of sets we denote by
the set of all points which belong to infinitely many lim inf En
En
lim sup ^
and by
the set of points which belong to all but finitely many of the
En* we limit of the
that the characteristic function oflim sup ER is the upper characteristic functions of the En , and likewise for the
lower limit. (2 2 .6 )
COROLLARY. E 1, E 2 , ... lim sup En For
by (17-8). (2 2 .7 )
and
X tj -p = nn
mE ^ 0q .
0^.;
lim inf En
Then
U nEn , D nEn ,
are measurable sets.
duallY* whence the conclusion follows
COROLLARY. measure
Let (22.1[a]) hold, and let
be measurable sets.
Let (22.1 [ f"; and Let
in
N
h
N be the set
then by hypothesis u - 1
mN - 0q . Since
L-function
is defined and
1
f•
0
elsewhere.
and a
is a non-nega.tive
be the function which has the value
and is
f»
u(t) -
For each positive integer
n, I(nxN ) - nI(xN ) - n0Q - Qq , so using (13-1), O q ^ K l n x ^ l A t u - 1]) < I(nxN ) By (U.it), 1(h) - lim I([nxn ] A f u - 1]) - 0^. Let s be the function which has the value f 1 (x) + h(x) whenever this is defined and the value
u(x)
elsewhere.
By
(22.2),
I(s) < I(f1) + T(h) = K f ^ But where case
.
f ^ t ) + h(t) is defined we have either t
f2 (t) = f ^ t ) * f ^ t ) + h(t),
or else
t
in
not in N,
N, in which
in which case
23f2 (t)
f ^ t ) + [u(t) - 1(t) ] «■ f ^ t ) + h(t);
undefined we have
f2(t) < u(t) = s(t).
Interchanging the roles of so N
f1
and
So
f2
f2 ^ s,
f ^ t ) + h(t)
and
and
0
elsewhere. U-function
By (1^-3), 1(h)
u1 ^
I(f2) £ K f j)-
= lim I(nx^) = 0q ,
u is in
^
1 ’ ui ^
(2 2 .1 6 )
THEOREM. Let (22.1 [a]) hold.
(i *
let
2),
such that
I(f) .
g
are equivalent.
Then
N
f
and
be the subset of T
elsewhere. Nk
Then
be the set
d]> o, (t : t
T and
f
and
23-
(2 3 .1 )
1)
there is a
g
be
and
g
are different.
for
t
on
N
and
For each positive integer
d(t) > 1/k).
Then Since
MEASURABLE FUNCTIONS AND LEBESGUE LADDERS
A function (of degree
on
is in
I(g') ®
0 £ ( 1 A ) X N < d, so I([lAl X N ) “ and mNk - 0^. k k N » mN = 0^, and f and g are equivalent. j
so
1
and
to g(t) - f(t)
and 1(d) » 0^. in
f
g ^ f
on which
and
»
and hypothesis (a) is
Let
F
d be the function which is equal o
N[> f 1 ]
summable members of
Let Let
^ u + ui
is
establishes the reverse inequality,
L[< then verified.
k
and where
I(f2) = T(fj). The other equation is established dually. If hypothesis (b) holds, let h be the functionwhich is
summable
to
87
MEASURABLE FUNCTIONS AND LEBESGUE LADDERS
if
0
on a vector space is called positively homogeneous
0(kx) = k0(x)
when
k > 0.
THEOREM. Let (22.1 [a]) hold.
Let
0 *
(^(y.,, •••, yn ): 7± real, i - 1 , ..., n) be a func tion of Baire defined and positively homogeneous on n-space. functions. (^(f^t),
Let
f 1, ..., f
be finite-valued measurable
Then the f■unction ..., fn (t)): t
in
0(f) = T)
is measurable
By (17-7), (19*3) and (19 •**■), if 0 is a homogeneous linear combination of the y^ or is a lattice combination of such linear combina tions, the conclusion holds. on the set
Zly^l = 1
By the Stone-Weierstrass theorem [Stone 2],
every continuous function can be uniformly approxi
mated by such lattice combinations. Hence if 0 is positively homogeneous and continuous, we can find a sequence of lattice-combinations 0 1, 0 2 ... such that limn 0n (f (t)) = 0(f(t)) for all t; and by (17*8) measurable. The extension to Baire functions is immediate.
0(f)
is
88
V.
(2 3 .2 )
Let (2-1 . 1 [a]) hold and let the whole
THEOREM. space
T
REAL-VALUED FUNCTIONS
be a measurable set.
Let
0 =
(^(y1 > • ••> yn ): r eal, 1 * 1 , ..., n) be a Balre function on n-space. If f 1, ..., f are finite 0 (f 1, ..., f )
valued and measurable, If
0
is measurable.
a + b 1 y 1 + ... + bnyn ,
is a linear function
1
sion is valid by (22.k), since the function identically
the conclu
is measurable.
All lattice combinations of such functions are measurable, by (1 7 .8 ). the Stone-Weierstrass theorem, If Integer
m
0
It can be approximated to within
{y : -m < y^ < m, 1 * 1 ,
..., n}
By
Is continuous for each positive l/m
on the interval
by such a combination
lim 0 (f(t)) = 0(f(t)) for all t, n->oo of all functions for which 0 (f)
and
0(f)
0 m . Hence
is measurable.
The set
is measurable contains all continuous
functions and is closed under passage to the limit, so it contains all Baire functions. (23.3)
Let (2 2. 1 [
an = 00,
llm
llm a_n = - ». n —*00 n —»00 By the "mesh” of the ladder we shall mean the supremum of the numbers
an - an _1, n = o ,
+i,+2,
... .
If we try to follow the familiar "ladder” method of defining the integral with the help of the measure, we find a difficulty when
T
lacks
finite measure that can be overcome, but by a device which we would prefer to avoid using when
T
has finite measure.
We succeed in treating each
case in the desired manner by tjie following artifice. Lebesgue ladder. all integers.
If
If
T
T
n
Is at least equal to the length N(A) • Let f be in
(t: an 1 < f(t) < an )
Let
F.
L
*
A
be a
shall mean the set of N(A)
such that the distance from
A summation designated by a sign subset of
N(A)
does not have finite measure,
of all those Integers [an 1,an ]
has finite measure,
an - an_1
0
shall consist to the Interval
of the interval.
shall mean a summation over some
If for each
n
in
N(A)
the set
has finite measure, and the finite sums
^ ' n = - h bn “ {t ! an-1 < f(t) i an } converge to a limit as associated with
f
and
h, k —* 00, A,
this limit Is called the "Lebesgue sum"
and is designated by
X;g that
exist; otherwise
in
G.
m*E
m*E
is not
»
such that
^ g
for all
Then for each subset
to be
m*E = 00.
m*(E1 U E 2) < m*E1 + m*E2
Also, if
»
I(Xg)
If it
E
ii summable
of
in we
U-functions
We readily prove, by use of (22.2),
for all sets E 1,E2
contained in
it is the infimum of m E f for all sets
finite measure which contain
g T
T. E'
of
E.
Starting with the exterior measure, we can construct a theory of measure according to Caratheodory1s procedure.
The relationship with our
theory is as follows. (23.8)
THEOREM.
Assume that (22.1[a]) and hypothesis (i)
of (23.6) hold, that a subset of E*
of
T
T.
T
If
E
is measurable, and
that E
is
is measurable, for every subset
the equation
(*)
m*(E* f\ E) + m*(E' - E) = m * E ! is satisfied; and if (*) holds whenever measure,
E
E'
has finite
is measurable.
As already remarked, the left member of (*) is prove the first conclusion, it remains to show that if the reverse inequality holds. Since
E
and
be a summable I(u A x e )
and
1
xE
and
1 - Xg
exist; their sum is
are measurable.
Let
I(u) .
But
. “ x A x < u A x > E'AE E' E = E
and similarly
x E'-E “ xE' A[ 1 - xE ^ =< uAti - xE 1 > so
m*(E' A E) + m*(E* - E) < I(u) . From the choice of
that the left member of (*) is of the first conclusion.
f2
E,
= Jo {ev
to mean
f 1 3 f2,
while
f° 3 f2 . Let
G
be the real number system.
easily verified and
G
is normal.
f1 »
f2
shall
Then (12.ia,b,c,d) are
In order to Investigate (12.ie) (which is the same as (8.1e)) we first prove a lemma. (25.3)
LEMMA. If S is a subset of F directed by » , then V S = V(f°: f in S) ; if S is a subset of F
directed by « Let
S
then
be ordered by
A s = A ( f C: f »,
and let
95
in p
S) .
belong to
VS;
then
p
96
VI. APPLICATIONS
belongs to some in
S
f
such that
\/{f0 : f
in
In
S.
g »
S),
Since S
f .Then
p
is directed by » , is in
f
V S C V(f°: f
so that
and
in
there exists
g
f C f° C g° C
S).
The reverse Inclusion
is evident, so the first statement Is established. If ordered by
S
Is ordered by
».
VtT - fc : f
the set S' = {T - f: fin
Hence, Vs* = V((T - f)°: f S 3 = T - A(f°: f
in
V t T - f: f
«,
Since
S 3 = T - /\if: ** inS 3 = T - /\S,
in
is
S3 =
in
in S 3 .
S)
\/S» = this proves the
second statement. Now let
S^Sg
tively, such that compact,
be subsets of
A S 2 < V S 1 . Each
by (25.1 iii).No point can
E
directed by
set
» , «
e2 - e° with
ei
respec In Si
is
belong to all sets
e2° - e^0 (e^ in S^); hence finitely many such sets e2°j “ e i°j (j == 1, ..., k)have an empty intersection. Choose e2 in S2 such that e0 «
e0 . (i = 1, ..., k); choose e- In S- such that e. » e. . ^ c o 1 1>J (j = 1 , ..., k ) . Then e 2 - e 1 is contained in all the sets
e°2 • - e°1 y
hence is empty.
Consequently
!0 (e2) < IQ(e}) . Hence A l Q (S2) ^ without the restriction to countable sets If k «
h,
k
is In
F
and
k
Is
h°.
their union Is an are in
e
F,
in
E
Is In
ii) interior to an
Finitely many such
e
such thatk «
and
S^.
compact, and h
each point ofk is by (18.1
closure is in
e°2 C e°1, e2 C e 1,
and ( 8 .1 e) isestablished,
,
e
F, and in E
whose
have Interiors which cover e «
h.
Since the
k;
empty set
and
T
this implies (8.if); and since mid
(e^e^e^)
E
d 12
e^»e2 anc* are, this implies (8 .1 g) . Let e^,e2,e^ belong to E. Write d 1 for for e 1 \J e2 - e^, and ^ 12^ for e1 A e2 f) e^,
the other
d^j
being analogously defined.
is
in
when
likewise for
e2
and
ey,
Then
and also
e1 - e2 \j e^,
e 1 = d 1 + d 12 + d ^ e 1\J e2 \J
d^
+ d 12^,
and
and
= d 1 + d2 + d^ + d 12 +
d 13 + d 23 + d 1 2 3 ' and mld (ei>e2 »e3 ' = d 12 + d 23 + d 13 + d 1 2 3 * By (25.1), r 1£ 1 ^(©i) * I0 (e ! u e2 u e3^ + (e1,e2,e^)) + IQ (e1 fl e2 A e^) . From this we see at once that (12.ih) is satisfied. Moreover, by a similar but easier argument we show that (12.7) also holds. We can now apply the results of the ^theory previously developed. First we shall look at the structure of sets which are U-elements. (25.M
L-elements or
THEOREM. An element f of F is a U-element if and only If it is an open set; it is an L-element if and only if it is a compact set. Assume
directed by
f
to bea
» such that
U-element; V s = f.
let
S
By (25.3),
be a subset of f = V(©°: ©
E in
S 3,
25. hence is E
open.
Likewise, if
so is compact. in
E
and
e« e
p
Thus
VS.
compact. E
If
p
e
of
p*
of
- f,
and
in E
e
»
and
T - f
If p
pis in
isa
to
and
be a subset of in
S},
open. By (8.2d), the set
that
e°
U-element.
each p
in
is in
and
ofE
cover
f,
there is
ec C f° =
Next assume
f, and e »
p*
f)
is not in
e. «,
hence
e
in
finitely
their union is an
is directed by
AS;
is not in
f,so
f
f corresponds an
f;
and
S =
ec C T - Ip*).The interiors of
e 1, ..., en
E,
S = te: e
point
T
is in e°
many such elements set
such
f = VS, and
p*is in
such that
element
E
S
f = A(ec: e
f ) is directed by » .
in
97
L-element, let
Conversely, assume f
by (25.1ii) an is in
f is an
such that A s = P.Then
> 1 .
for which
1 ,1 , 1
The symbols
E e
and of
e «
E
u) .
Thus
for which
I-j(l)
I 1 (u)
e«
Is an L-element (that is,
is necessarily summable, and of
IQ (S)
u.
if
is
has the same value for all such sets ^S,
(e: e
supremum of
e
for which
in
is the This is
acompact set), it
Is the infimum of
IQ (o)
This is the same as
1 (1 ) .
will be replaced by
m,m*,m#
for all sets
respectively
(read measure, exterior measure, interior measure respectively). According to the foregoing, the measure of an open set is the supremum of the ele mentary measures
IQ (e)
of all sets
e
of
E
whose closures are in the
open set, provided this supremum is finite; the measure of a compact set is the Infimum of the elementary measures whose interiors the compact the Infimum of
mu
I0 (e)
1
e
of
set lies; the exterior measure of a set
for all open sets
u
contained in
f.
If
E
In
f
is
of finite measure containing
if such sets exist; the interior measure of all compact sets
se"^s
f
m*f
is the supremum of and
common value (necessarily finite) is denoted by
mf,
m*f
f
ml
for
are equal, their
and
f
is said to
have finite measure. If so are
f1
and
f 1 U f2 and
It is easy to show o.
So if
f1
and
f2
are sets of finite measure, by (1 5 -1 ) and (15-2)
f 1 A f2,
and
m(f1 \J f2) + m^f1 fi f2) = mf 1 + mfg.
that the empty set has finite measure, namely measure f2
are disjoint, the above equation yields m(f1 U f2 ) = m f 1 + mf2 .
Condition (1^.1) obviously holds. By (1 h .3 ), if Is a sequence ofsets of finite measure such that union
f 1, f2 , f^, ...
f 1 C f2 C f^ C ...,
Unf n is a set of finite measure If and only If the numbers
the
98
VI• APPLICATIONS m( \Jn?n) = V^mf^ = lim mf^. are necessarily i — » 00
mf 1 , mf2 , ... are bounded, in which case If f 1 f2 zd f^ o ..., the numbers mf^ bounded, so if
flIIfi l in
A)
is of finite measure, and
m( fLf-J = Ii Ii
•
lim
is a directed system of sets of finite
all contained in a set
f”
mfL1 . Also,
00 measure,
a o*-convergent to a set
of finite measure and
f , by (1 5 *1 ) f~Q has finite measure, and mfQ = lim mf^. (We choose f' to be the empty set in hypothesis (ii) of a Ink (15.-1)). By (1 7 -1 ), a set
f
sets of finite measure with f] U (f2 0 f) f2 f\ f
the set
mid (f1,f2,f) =
has finite measure.This clearly implies
finite measure, since we can choose if
f.j to be the empty f 1 U (fg 0 f)
has finite measure, so does
finite measure.
°^
is measurable if for all pairs
f 1 C f2,
that
f2 f\ f
set.
Conversely,
whenever
So a necessary and sufficient condition that
measurable is that
f2 fl f
have finite measure whenever
f2
f
f1
has has
be
has finite
In particular, by (1 7 *5 ) all open sets and all compact sets are
measure.
measurable. We now stopto prove (25.5)
LEMMA. g
a lemma.
Let f
be a subset of
be a set of finite measure and let f.
Then
m*(f - g) =
mf - m*g and
m*(f - g) = mf - m*g. Let€ and a compact 1 - u
be a positive number. set
1 C f
There exists an open set
such that mu< m*g + e
is a compact subset of
f - g,
and 1 C\ u
m*(f - g) > m(l - u) = m(l - 1 0 u)
and
u o g
ml > mf - e .
Then
has finite measure,
so
= ml - m(l fl u) ^ ml - mu >
mf - m*g - 2 6 . Hence
m# (f - g) ^ mf - m*g.
such that that tains
mu < mf + €,
m l 1 > m*(f - g) g, and
Next, let
and let - e. Then
1* be l 1 C u,
m*g < m(u - l 1)= mu - ml*
u be an open set containing a compact subset of f - g
f such
and
u - 1 * is open and
< mf
- m*(f - g) + 2€.Hence
con
m*g < mf - m*(f - g) . With the previous inequality, this establishes the first conclusion. The second is obtained by merely interchanging g and f - gAs a corollary we have (25.6)
THEOREM. has If
f - g; g C f
If and if
fand
g have finite
measure, so
g C f, m(f - g) = mf - mg.
the preceding lemma shows that
m*(f - g) =
25.
MEASURE IN LOCALLY COMPACT SPACES
m*(f - g) = mf - mg,
establishing the second conclusion; if f f) g,
finite measure so has f - f H g, ment
f2 - f 2 Pi f,
For let
f2
f
f2
bas.
have
is measurable, so is its comple
have finite measure; then
which has finite measure, and so
measure whenever
f,g
and by the second conclusion so has
which is f - g. Prom this it follows that If
T - f.
99
f2 fl(T - f) =
f2 A (T - f)
has finite
Now the family of measurable sets contains all
compact sets and all open sets, and is closed under complementation and under formation of countable unions and intersections. tains all Borel sets in
Let us extend the definition of ever
f
It therefore con
T. m*
by setting
m*f =
in
H;
clearly
To show that it satisfies (1 .1b), (that is, is proper)
we make a simple calculation: (28.1) H,
LEMMA.
If
B
is a bounded linear operation on
and
and
y
are in
x
H,
then
2 (Bx,y) = (B[x + y],[x + y] ) + i(B[x + iy],[x + iy]) - (1 + i) [(Bx,x) + (B y ,y )] . Now if
B" ^ B *
and B 1 )
(Bx,x) = 0
for
all x
x
in H,
whence
and
(28.2)
y
LEMMA.
in
Let
B", then the difference
B = B" - B * satisfies
H, so by (28.1) we have (Bx,y) = 0 B = 0. S
Thus
>
for all
is a (proper) partial ordering.
be a subset of
G
directed by
>
1 09
2 8 . REMARKS ON OPERATORS IN HILBERT SPACES and having an upper hound
B*
in
G.
exists a hounded hermitian operator (
I)
(Cx,x) « \/((Bx,x) : B
( ii )
in H; lim (Bx,y) = (Cx,y) B in S y in H;
(ill)
c - Vs.
Then there
C in
such that S) for each
x
For each
x
in
H,
((Bx,x)
:B
for each
in
S)
x
and
is an isotone net of
real numbers, so has a limit which is its supremum.
Each term in the
right member of the equation in (28.1) has a limit, so for each in
H
the net
B ” < B < B f. BQ
of
in
H.
G,
(Bx,y) Let
M
I|Bq ||
he the larger of x,
I|B| I < M.
eventually
Thus for all
I(Bx,y) | < M * |x| •|y| , the unit sphere. in
y,
y
H.
(C[kfx* + H
x
x
and
H
we eventually have
(Bx,y) x
x
(B*x,x) < M,
is hounded for x,y
the function(y,Bx)
in
is linear
Cx.
Thus
with some element of
lim (Bx,y) = (Cx,y)
If in particular we choose so (Cx,y)
y
y = Cx, y
the function
is also linear in
] - k*Cxf - k"Cx", y)
for all
x.
We have already shown it hounded.
and
(Bx,y)
is
Thus
vanishes for all elements
k',k”, whence
x
the previous estimate shows
C
is a
x*,x",y
linear trans
Also, for all
a and
y
H, (Cx,y) = lim (Bx,y) = lim (x,By) = lim (By,x) = (Cy,x) = (x,Cy)
so
C
is hermitian.
,
This completes the proof of conclusion(ii) .
Con
clusion (i) follows at once, by the second remark after (3-1)* By (i), an upper bound for
C S
is an upper bound for in
G-
Then for all
S x
in in
G. H
Let C* he also
we have
(Bx,x) for all B in S, so by (i) (C'x,x) > (Cx,x), This establishes (iii) and completes the proof.
and
(C*x,x) > C* > C.
This lemma allows us to prove that in G, o-convergence is equivalent to eventually-bounded strong convergence: (28.3)
y
eventually
for all unit vectors
the inner product of
and all complex numbers
formation. in
S,
the same is true of its limit; being hounded on the unit sphere,
linear in x, of
x,y in
|Cx| < M -1 x| . Also, for each fixed
that
is in
-M (B"x,x) < (Bx,x)
Jn
this approaches
6
>
0 . Hence the 0 . The result
is some fixed element
... J . dn (k,)'3' •••( V ' 3” jn= 0
o = 0’
IQ each such factor
as
. . s
k 1, ..., kn
■
Increase
31 •
RESOLUTION OF REAL ALGEBRAS
129
(cf. (7-4)), so IQ(e) ^ and (2 2 .le) is established. The proof of (2 2 .if) is essentially the same as in, say, Section 2 6 , so all of postulate (2 2 .1 ) holds. Hence we can define an integral I on a subset Fsuln of F, having all the properties established in Section 22 and earlier sections. In particular, (1 5• ^) holds for each eQ in E; we need only take e| = eQ - 1/1, e£ = eQ, e'^' = eQ + 1 /i, i = 1, 2 , 3 , ••• • So 1(e) = IQ(e) for every e in E, which implies conclusion (vi). Conclusion (I) follows from (22.4), and (ii) from (1 5 .1 ). It is not difficult to show that a function is a U-function If and only If it is bounded below and lower semi-continuous. In particular, the characteristic function of an open set is a U-function, so by (17*5) is a measurable function. Thus all open sets are measurable. In par ticular, with e = 1 , we obtain mT = I (1 ) « u. Since differences, countable unions and countable intersections of measurable sets are measurable, all Borel sets are measurable. Consequently all Borel-measur able functions are measurable, which implies (iii). Conclusion (v) follows at once from (19-5) • In particular, if 2 f is the characteristic function of a measurable set M, then f = f , so by (v) 1(f) = [1(f)]2, that Is, mM = (mM)2 ]> 0. If f1 and f2 are the characteristic functions of measurable sets M 1 and Mg respec tively, f^ f2 is the characteristic function of M 1 fl Mg, so (mMr)(inM2) - m(M1 fi M2), and (vii) is established. Suppo'se that f Is summable (hence measurable) and that 1(f) y 9, but m(t: f(t) < 0 ) ^ 0. Since m{t: f(t)< 0} = o-lim m(t: f(t) < -1/n), there exists a positive integer n such that n —1i 00 ~ the set M = (t: f(t) ^ -1/n) has measure mM ^ 9. Then on the one hand I(f • XM ) = I(f)I(xM ) = I(f)mM > 9. so
I(f •
On the other hand,
i -n ’1l(X M ) =
f • X M < -Xj/n,
.
Combining these estimates yields -n-1mM > 9, whence mM < 9. But by (vii) mM y_ 9 , so mM = 9, which is a contradiction. This establishes the first sentence In (viii). If f is summable and has a lower bound -b, and the set N * (t: f(t) < 0) has mN = 9 , then the function f + bxjj is ^ 0 on T, so 9 < I(f + byN ) = Kf) + bI(xN) = 1(f) + bmN * 1(f), establishing the second sentence. If f1 and f2 are bounded and equivalent, and f1 is summable, so Is f2 by (2 2 .1 5 ). The sets (t: f2(t) - f1(t) < 0} and Ct: f1(t) - f2(t) < 0 } both have measure 9, so by the proof just completed we have I(f2 - f 1) ^ 0 and I(f1 - fg) > 9, establishing the third sentence of (viii).
130
VI. APPLICATIONS Suppose that f 1
and
f2
are summable and fInite-valued, and
I(f1) =I(f2) . By the first sentence of (viii), both - f2 (t) < 0 }
m(t: f^t)
m(t: f2 (t) - f ^ t ) < 0 }
and
Hence the union of these sets, which is 0,
are equal to
(t: f ^ t ) / f2 (t)},
0.
has measure
establishing the last sentence of (viii).
Returning to (iv), we let K be the subset of A consisting of those elements x to which there corresponds a bounded function of Baire f such that 1 (f) = x. All elements of the and having an upper bound; it then has a supremum V S in A. By (2 .1+), we may suppose that S is an isotone sequence x 1 < x2 < ... converging to VS. To each xR corresponds a bounded function of Baire f^ such that = xn* ^e^ a a num1:)er such that V s < au. Since xn £ cu for each n, by (viii) we have f^ < c except on a set of measure 0 . Hence f^ Is equivalent to A c, which Is a Baire func tion; and by (viii) K f ^ A c) = xR . That is, we may as well suppose that all the f^ satisfy f^ < c to begin with. Next we define inductively f 1 = f j, ..., fR = f^ V fn_-, • There are clearly Baire functions. The relation 1 (f) = xR holds for n = 1 by definition. If it holds for n = k -1 , then > xk-1 = K f k_i), so by (viii) f£(t) >fk-i(t) except on a set of measure 0 , and f£ isequivalent to V f^, which is f^. Then by (viii) = = xk* anc^ 30 by induction we have Kf*n) = *n for all n. Since f 1 < f2 ... j( c, they have a limit f which is also a Baire function and is < c. By (ii),
= °_lirn
= 0_liin xn =
In a like manner, if
S
having an infimum in
A,
cr-complete.
Hence
is a countable subset of
AS
Is in
K.
Hence
K
K
Vs
is also in
directed by